Pharmacology & Dosage
Intermediate

Drug Half-Life

Time for the plasma concentration of a drug to fall to half its initial value.

Formula

t1/2=0.693ket_{1/2} = \frac{0.693}{k_e}

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Variables

t_{1/2}Half-life
k_eElimination rate constant
0.693ln 2

Example

kₑ = 0.1/hr → t½ = 6.93 hours

How it works

Drug half-life is the time it takes for a drug’s plasma concentration to drop by 50% when the body removes it by first-order elimination. The constant 0.693 is ln 2, which appears because first-order decay is exponential: after one half-life, the amount remaining is exactly half of what it was. Since the elimination rate constant ke tells you how quickly the drug is cleared per unit time, dividing ln 2 by ke gives the characteristic time for the concentration to halve.

When to use it

Use this formula when a drug follows first-order kinetics and you know the elimination rate constant from pharmacokinetic data. It is helpful for estimating dosing intervals, time to steady state, and how long a drug will stay in the body after dosing stops.

Worked example, step by step

Given: ke = 0.25 hr^-1 Step 1: Write the half-life formula: t1/2 = 0.693 / ke Step 2: Substitute the value: t1/2 = 0.693 / 0.25 Step 3: Calculate: t1/2 = 2.772 hours Final answer: The drug half-life is about 2.77 hours.

Common mistakes to avoid

  • Using this formula for zero-order elimination, where half-life is not constant
  • Mixing up the elimination rate constant ke with clearance or dose
  • Forgetting that ke must have time^-1 units, otherwise the half-life calculation will be inconsistent

Did You Know?

After five half-lives, about 97 % of a drug has been eliminated — this '5 half-lives' rule guides how long drugs stay active.

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Reviewed & maintained by the FormulaWon editorial teamLast reviewed September 2026