Materials & Civil
Intermediate

Young Modulus

Ratio of stress to strain; measures material stiffness.

Formula

E=σεE = \frac{\sigma}{\varepsilon}

Variables

\sigmaStress
\varepsilonStrain

Example

Steel: ~200 GPa

How it works

Young’s modulus tells you how much a material resists elastic stretching or compression: a larger value means the material deforms less for the same applied stress. It works because, within the elastic limit, many solids show an approximately linear relationship between stress and strain, so their stiffness can be captured by a single ratio. In other words, it compares how much force per area is applied to how much proportional deformation results.

When to use it

Use this formula when you need to compare the stiffness of materials or predict elastic extension/compression in engineering and physics problems. It is especially useful for metals, rods, beams, and wires when the deformation is small enough that the material remains in the elastic region.

Worked example, step by step

A copper rod experiences a stress of 80 MPa and a strain of 4.0 × 10^-4. E = σ / ε E = (80 × 10^6 Pa) / (4.0 × 10^-4) E = 2.0 × 10^11 Pa E = 200 GPa So, the Young modulus of the rod is 200 GPa.

Common mistakes to avoid

  • Using force instead of stress; stress must be force divided by cross-sectional area
  • Forgetting that strain has no units, so the answer must come out in pascals
  • Applying Young’s modulus beyond the elastic limit, where the stress-strain relationship is no longer linear

Did You Know?

A high Young modulus means a stiff, less stretchy material.

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Reviewed & maintained by the FormulaWon editorial teamLast reviewed September 2026