Cantilever Beam Deflection
Maximum deflection of a cantilever with an end load.
Formula
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Example
Deflection grows with the cube of length
How it works
This formula gives the downward tip deflection of a slender beam that is fixed at one end and carries a single point load at the free end. It comes from Euler-Bernoulli beam theory, where bending curvature is related to the applied moment; integrating that curvature along the beam with the fixed-end boundary conditions produces the cubic-length relationship. The result shows that a beam gets much more flexible as it gets longer, but stiffer materials and larger second moments of area reduce the deflection.
When to use it
Use this for long, slender cantilever members under a concentrated load at the free end, such as a bracket, diving board, shelf support, or overhanging structural arm. It is appropriate when deflections are small, the material behaves elastically, and the beam has roughly constant cross-section.
Worked example, step by step
Given: F = 800 N L = 2.5 m E = 200 GPa = 2.0 × 10^11 Pa I = 8.0 × 10^-6 m^4 Step 1: Write the formula δ = FL^3 / (3EI) Step 2: Compute L^3 L^3 = (2.5)^3 = 15.625 m^3 Step 3: Substitute values δ = (800 × 15.625) / (3 × 2.0 × 10^11 × 8.0 × 10^-6) Step 4: Calculate the denominator 3 × 2.0 × 10^11 × 8.0 × 10^-6 = 4.8 × 10^6 Step 5: Calculate the deflection δ = 12500 / 4.8 × 10^6 = 2.604 × 10^-3 m Final answer: δ ≈ 0.00260 m = 2.60 mm
Common mistakes to avoid
- Using the formula for a distributed load instead of a single end load
- Forgetting to convert units so E, I, L, and F are all in a consistent system
- Confusing the second moment of area I with mass moment of inertia
Did You Know?
Doubling the length increases deflection eightfold.
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