Bending Stress
Stress in a beam due to a bending moment.
Formula
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Example
Max stress occurs at the outer fibers
How it works
When a beam bends, one side is stretched and the other is compressed, and the normal stress varies linearly with distance from the neutral axis. The formula \(\sigma = \frac{Mc}{I}\) comes from combining that linear strain distribution with Hooke’s law and the internal moment balance of the cross-section. It shows that larger bending moment increases stress, while a larger second moment of area makes the section stiffer and lowers stress for the same load.
When to use it
Use this when you need the bending stress at a particular point in a beam cross-section under a known bending moment, such as in beam design, failure checks, or verifying whether a member can safely carry a load. It is especially useful in structural, mechanical, and civil engineering problems involving prismatic beams.
Worked example, step by step
A steel beam is subjected to a bending moment of M = 18 kN·m. The point of interest is 75 mm from the neutral axis, so c = 75 mm = 0.075 m. The second moment of area of the cross-section is I = 8.0 × 10^-6 m^4. Use σ = Mc/I. Substitute the values: σ = (18,000 N·m)(0.075 m) / (8.0 × 10^-6 m^4). Compute the numerator: 18,000 × 0.075 = 1,350 N·m^2. Divide: σ = 1,350 / (8.0 × 10^-6) = 1.6875 × 10^8 Pa. Final answer: σ ≈ 169 MPa, tensile or compressive depending on which side of the neutral axis the point lies on.
Common mistakes to avoid
- Using the beam depth instead of the distance from the neutral axis for c
- Mixing units, especially kN·m with mm^4 without converting consistently
- Assuming the formula gives the same sign everywhere instead of tension on one side and compression on the other
Did You Know?
I-beams put material where bending stress is highest.
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