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Bending Stress

Stress in a beam due to a bending moment.

Formula

σ=McI\sigma = \frac{M c}{I}

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Variables

MMoment
cDistance to neutral axis
IMoment of inertia

Example

Max stress occurs at the outer fibers

How it works

When a beam bends, one side is stretched and the other is compressed, and the normal stress varies linearly with distance from the neutral axis. The formula \(\sigma = \frac{Mc}{I}\) comes from combining that linear strain distribution with Hooke’s law and the internal moment balance of the cross-section. It shows that larger bending moment increases stress, while a larger second moment of area makes the section stiffer and lowers stress for the same load.

When to use it

Use this when you need the bending stress at a particular point in a beam cross-section under a known bending moment, such as in beam design, failure checks, or verifying whether a member can safely carry a load. It is especially useful in structural, mechanical, and civil engineering problems involving prismatic beams.

Worked example, step by step

A steel beam is subjected to a bending moment of M = 18 kN·m. The point of interest is 75 mm from the neutral axis, so c = 75 mm = 0.075 m. The second moment of area of the cross-section is I = 8.0 × 10^-6 m^4. Use σ = Mc/I. Substitute the values: σ = (18,000 N·m)(0.075 m) / (8.0 × 10^-6 m^4). Compute the numerator: 18,000 × 0.075 = 1,350 N·m^2. Divide: σ = 1,350 / (8.0 × 10^-6) = 1.6875 × 10^8 Pa. Final answer: σ ≈ 169 MPa, tensile or compressive depending on which side of the neutral axis the point lies on.

Common mistakes to avoid

  • Using the beam depth instead of the distance from the neutral axis for c
  • Mixing units, especially kN·m with mm^4 without converting consistently
  • Assuming the formula gives the same sign everywhere instead of tension on one side and compression on the other

Did You Know?

I-beams put material where bending stress is highest.

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Reviewed & maintained by the FormulaWon editorial teamLast reviewed September 2026