Max Moment (Simple Beam, UDL)
Maximum bending moment for a simply supported beam under uniform load.
Formula
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Example
Peak occurs at midspan
How it works
For a simply supported beam carrying a constant load intensity across the full span, the internal bending moment builds up from the supports toward the middle because the shear force decreases linearly. The largest moment occurs where the shear force crosses zero, which is at midspan for a symmetric uniform load, giving M_max = wL^2/8. The result comes directly from integrating the load to get shear and then integrating shear to get bending moment.
When to use it
Use this for straight beams with pin/roller supports when the load is evenly distributed over the entire span, such as floor joists, bridge members, or roof beams carrying uniform dead load. It is most useful when you need the peak bending moment for stress checks, sizing, or deflection calculations.
Worked example, step by step
Given: w = 3.5 kN/m, L = 6.0 m Step 1: Square the span: L^2 = (6.0)^2 = 36.0 m^2 Step 2: Multiply by the load intensity: wL^2 = 3.5 × 36.0 = 126.0 kN·m^2/m Step 3: Divide by 8: M_max = 126.0 / 8 = 15.75 kN·m Answer: The maximum bending moment is 15.75 kN·m, occurring at the center of the beam.
Common mistakes to avoid
- Using the total load wL instead of the load intensity w in the formula
- Forgetting to square the span length, which causes the moment to come out too small
- Applying the formula to a cantilever or non-uniform load case where the moment diagram is different
Did You Know?
This midspan formula is a staple of structural design.
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