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Sabine Reverberation Time

Time for sound to decay 60 dB in a room.

Formula

RT60=0.161VART_{60} = 0.161\frac{V}{A}

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Variables

RT_{60}Reverb time (s)
VRoom volume (m³)
ATotal absorption (m² sabins)

Example

V=200 m³, A=40: RT = 0.161×5 ≈ 0.8 s

How it works

Sabine’s reverberation-time formula estimates how long it takes sound energy in a room to drop by 60 dB after the source stops. It comes from a simplified energy-balance model: larger rooms store more sound energy, while more absorbent surfaces remove that energy faster, so reverberation time grows with volume and shrinks with total absorption. The constant 0.161 is specific to SI units and arises from the speed of sound and the conversion between energy decay and decibels in Sabine’s derivation.

When to use it

Use this formula when designing or evaluating rooms where clarity and echo matter, such as concert halls, classrooms, studios, lecture rooms, and theaters. It is most appropriate for moderately diffuse fields and surfaces with relatively even absorption, not for highly irregular spaces or very small, very absorptive rooms.

Worked example, step by step

Step 1: Identify the room volume and total absorption. V = 350 m³ A = 70 m² sabins Step 2: Substitute into Sabine’s formula. RT60 = 0.161 × V / A RT60 = 0.161 × 350 / 70 Step 3: Simplify the ratio. 350 / 70 = 5 RT60 = 0.161 × 5 Step 4: Calculate the result. RT60 = 0.805 s Final answer: The reverberation time is about 0.81 seconds.

Common mistakes to avoid

  • Using surface area instead of total absorption in sabins
  • Forgetting that the 0.161 constant is for SI units only
  • Applying the formula to a non-diffuse room where reflections are highly uneven

Did You Know?

Wallace Sabine founded architectural acoustics around 1900 while fixing a Harvard lecture hall's terrible echo.

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Reviewed & maintained by the FormulaWon editorial teamLast reviewed September 2026