Music & Acoustics
Intermediate

Sound Intensity Level (dB)

Sound intensity expressed in decibels relative to the hearing threshold.

Formula

L=10log⁡10 ⁣(II0)L = 10 \log_{10}\!\left(\frac{I}{I_0}\right)

Variables

LLevel (dB)
IIntensity (W/m²)
I_0Reference 10⁻¹² W/m²

Example

I = 10⁻⁶ W/m²: L = 10 log(10⁶) = 60 dB

How it works

This formula converts a physical sound intensity into a logarithmic scale called decibels, which matches how humans perceive loudness: equal ratios in intensity feel more similar than equal differences. The reference intensity I_0 = 10^-12 W/m² is chosen to represent the approximate threshold of human hearing, so the result tells you how many "power levels" above that baseline the sound is. The factor of 10 is used because decibels are defined for power-like quantities such as intensity.

When to use it

Use this when you know a sound’s intensity in watts per square metre and want its level in decibels. It appears in acoustics, noise measurement, audio engineering, and any problem comparing sound strengths on a perceptual scale.

Worked example, step by step

Given I = 3.0 × 10^-8 W/m² and I_0 = 1.0 × 10^-12 W/m² Step 1: Form the ratio I / I_0 = (3.0 × 10^-8) / (1.0 × 10^-12) = 3.0 × 10^4 Step 2: Take the base-10 logarithm: log10(3.0 × 10^4) = log10(3.0) + 4 ≈ 0.4771 + 4 = 4.4771 Step 3: Multiply by 10: L = 10 × 4.4771 = 44.771 dB Final answer: L ≈ 44.8 dB

Common mistakes to avoid

  • Using ln instead of log10
  • Forgetting that the formula uses an intensity ratio, not an absolute intensity
  • Using 20 log10(I/I0) instead of 10 log10(I/I0) for intensity

Did You Know?

Because it is logarithmic, a 10 dB rise sounds roughly twice as loud but carries ten times the power.

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Reviewed & maintained by the FormulaWon editorial teamLast reviewed September 2026