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Combining Two Sound Levels

Total level when two sound sources play together.

Formula

L=10log⁡10(10L1/10+10L2/10)L = 10 \log_{10}(10^{L_1/10} + 10^{L_2/10})

Variables

LCombined level (dB)
L_1Level 1 (dB)
L_2Level 2 (dB)

Example

Two 60 dB sources: L = 10 log(2×10⁶) ≈ 63 dB

How it works

Decibels are logarithmic, so you cannot add sound levels in dB directly. This formula converts each level back into a linear sound-intensity scale, adds those intensities, and then converts the result back into decibels. It works because dB is defined relative to a reference intensity, so equal-looking dB differences can correspond to very different physical power contributions.

When to use it

Use this when two independent sound sources are present at the same point and you want the resulting overall sound level, such as two speakers, two machines, or a background noise plus a new source. It is also useful in acoustics problems involving combined noise exposure or overlapping signals.

Worked example, step by step

Suppose one source is 58 dB and another is 64 dB. L = 10 log10(10^(58/10) + 10^(64/10)) L = 10 log10(10^5.8 + 10^6.4) L = 10 log10(630957 + 2511886) L = 10 log10(3142843) L ≈ 10 × 6.497 L ≈ 64.97 dB Final answer: the combined sound level is about 65.0 dB.

Common mistakes to avoid

  • Adding the dB values directly instead of converting to intensity first
  • Using the wrong logarithm base or forgetting the factor of 10
  • Assuming the louder source and the total differ by 3 dB regardless of the level gap

Did You Know?

Two identical sounds add only 3 dB, not double — doubling loudness needs ten sources, not two.

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Reviewed & maintained by the FormulaWon editorial teamLast reviewed September 2026