View solutions
FormulaWon

Tanzania · Grade 12 · Practice Sheet 35

Sheet code: TANZANIA-G12-S35 · 20 questions

Name: ______________
Date: ______________
  1. 1.

    TSh 3,000 is invested at 6% compound interest per annum for 3 years. Find the final amount (to 2 d.p.).

    Formula:Compound Interest
    A=P(1+r100)tA = P\left(1 + \dfrac{r}{100}\right)^{t}
    View formula →
  2. 2.

    Find the force needed to accelerate a 38 kg mass at 1.9 m/s².

    Formula:Newton's Second Law
    F=maF = ma
    View formula →
  3. 3.

    An object with initial velocity 4 m/s accelerates at 2.6 m/s² for 6 s. Find the distance travelled.

    Formula:Kinematics (s = ut + ½at²)
    s=ut+12at2s = ut + \tfrac{1}{2}at^2
    View formula →
  4. 4.

    Find the volume of a sphere of radius 12 cm. (π ≈ 3.14159)

    Formula:Volume of a Sphere
    V=43πr3V = \tfrac{4}{3} \pi r^3
    View formula →
  5. 5.

    A force of 69 N moves an object 26 m in the direction of the force. Find the work done.

    Formula:Work Done
    W=FdW = F d
    View formula →
  6. 6.

    Find the gravitational potential energy of a 41 kg object raised 33 m. (g = 9.8 m/s²)

    Formula:Gravitational Potential Energy
    PE=mghPE = mgh
    View formula →
  7. 7.

    Find the sum of the first 7 terms of an arithmetic series with first term a = 11 and common difference d = 8.

    Formula:Sum of an Arithmetic Series
    Sn=n2(2a+(n1)d)S_n = \tfrac{n}{2}\left(2a + (n-1)d\right)
    View formula →
  8. 8.

    Solve using the quadratic formula: x² + 1x − 12 = 0.

    Formula:Quadratic Formula
    x=b±b24ac2ax = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}
    View formula →
  9. 9.

    A 5 kg object moves at 15 m/s. Find its kinetic energy.

    Formula:Kinetic Energy
    KE=12mv2KE = \tfrac{1}{2} m v^2
    View formula →
  10. 10.

    Two masses 3,400 kg and 260 kg are 8 m apart. Find the gravitational force between them. (G = 6.674×10⁻¹¹)

    Formula:Newton’s Law of Gravitation
    F=Gm1m2r2F = G\dfrac{m_1 m_2}{r^2}
    View formula →
  11. 11.

    Find the volume of a sphere of radius 9 cm. (π ≈ 3.14159)

    Formula:Volume of a Sphere
    V=43πr3V = \tfrac{4}{3} \pi r^3
    View formula →
  12. 12.

    Find the gravitational potential energy of a 14 kg object raised 40 m. (g = 9.8 m/s²)

    Formula:Gravitational Potential Energy
    PE=mghPE = mgh
    View formula →
  13. 13.

    A triangle has sides a = 12 cm and b = 10 cm with an included angle C = 60°. Find its area (to 2 d.p.).

    Formula:Area of a Triangle (Sine Rule)
    A=12absinCA = \tfrac{1}{2} ab\sin C
    View formula →
  14. 14.

    Find the gravitational potential energy of a 45 kg object raised 14 m. (g = 9.8 m/s²)

    Formula:Gravitational Potential Energy
    PE=mghPE = mgh
    View formula →
  15. 15.

    Find the volume of a sphere of radius 4 cm. (π ≈ 3.14159)

    Formula:Volume of a Sphere
    V=43πr3V = \tfrac{4}{3} \pi r^3
    View formula →
  16. 16.

    Find the gravitational potential energy of a 37 kg object raised 4 m. (g = 9.8 m/s²)

    Formula:Gravitational Potential Energy
    PE=mghPE = mgh
    View formula →
  17. 17.

    In a triangle, a = 13, b = 5 and the included angle C = 110°. Find side c (to 2 d.p.).

    Formula:Cosine Rule
    c=a2+b22abcosCc = \sqrt{a^2 + b^2 - 2ab\cos C}
    View formula →
  18. 18.

    A 17 kg object moves at 6 m/s. Find its kinetic energy.

    Formula:Kinetic Energy
    KE=12mv2KE = \tfrac{1}{2} m v^2
    View formula →
  19. 19.

    Two masses 6,200 kg and 670 kg are 18 m apart. Find the gravitational force between them. (G = 6.674×10⁻¹¹)

    Formula:Newton’s Law of Gravitation
    F=Gm1m2r2F = G\dfrac{m_1 m_2}{r^2}
    View formula →
  20. 20.

    Find the population standard deviation of: 18, 7, 4, 18, 15 (to 2 d.p.).

    Formula:Standard Deviation (Population)
    σ=(xxˉ)2n\sigma = \sqrt{\dfrac{\sum (x - \bar{x})^2}{n}}
    View formula →

© FormulaWon — formulawon.app · Answers & step-by-step working available on the solutions sheet.