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Tanzania · Grade 12 · Practice Sheet 32

Sheet code: TANZANIA-G12-S32 · 20 questions

Name: ______________
Date: ______________
  1. 1.

    A triangle has sides a = 12 cm and b = 12 cm with an included angle C = 90°. Find its area (to 2 d.p.).

    Formula:Area of a Triangle (Sine Rule)
    A=12absinCA = \tfrac{1}{2} ab\sin C
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  2. 2.

    Find the volume of a sphere of radius 9 cm. (π ≈ 3.14159)

    Formula:Volume of a Sphere
    V=43πr3V = \tfrac{4}{3} \pi r^3
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  3. 3.

    A device runs at 240 V drawing 2.2 A. Find its power consumption.

    Formula:Electrical Power
    P=VIP = V I
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  4. 4.

    Find the force needed to accelerate a 58 kg mass at 1 m/s².

    Formula:Newton's Second Law
    F=maF = ma
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  5. 5.

    A device runs at 234 V drawing 6.9 A. Find its power consumption.

    Formula:Electrical Power
    P=VIP = V I
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  6. 6.

    Find the gravitational potential energy of a 16 kg object raised 7 m. (g = 9.8 m/s²)

    Formula:Gravitational Potential Energy
    PE=mghPE = mgh
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  7. 7.

    An object with initial velocity 12 m/s accelerates at 2.8 m/s² for 6 s. Find the distance travelled.

    Formula:Kinematics (s = ut + ½at²)
    s=ut+12at2s = ut + \tfrac{1}{2}at^2
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  8. 8.

    A triangle has sides a = 8 cm and b = 11 cm with an included angle C = 45°. Find its area (to 2 d.p.).

    Formula:Area of a Triangle (Sine Rule)
    A=12absinCA = \tfrac{1}{2} ab\sin C
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  9. 9.

    TSh 3,000 is invested at 6% compound interest per annum for 4 years. Find the final amount (to 2 d.p.).

    Formula:Compound Interest
    A=P(1+r100)tA = P\left(1 + \dfrac{r}{100}\right)^{t}
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  10. 10.

    Find the volume of a sphere of radius 4 cm. (π ≈ 3.14159)

    Formula:Volume of a Sphere
    V=43πr3V = \tfrac{4}{3} \pi r^3
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  11. 11.

    TSh 4,000 is invested at 4% compound interest per annum for 4 years. Find the final amount (to 2 d.p.).

    Formula:Compound Interest
    A=P(1+r100)tA = P\left(1 + \dfrac{r}{100}\right)^{t}
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  12. 12.

    A current of 6.2 A flows through a 35 Ω resistor. Find the voltage across it.

    Formula:Ohm's Law
    V=IRV = I R
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  13. 13.

    A force of 72 N moves an object 12 m in the direction of the force. Find the work done.

    Formula:Work Done
    W=FdW = F d
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  14. 14.

    Solve using the quadratic formula: x² − 4x + 0 = 0.

    Formula:Quadratic Formula
    x=b±b24ac2ax = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}
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  15. 15.

    A current of 2.8 A flows through a 48 Ω resistor. Find the voltage across it.

    Formula:Ohm's Law
    V=IRV = I R
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  16. 16.

    Find the force needed to accelerate a 25 kg mass at 3.2 m/s².

    Formula:Newton's Second Law
    F=maF = ma
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  17. 17.

    A triangle has sides a = 10 cm and b = 11 cm with an included angle C = 60°. Find its area (to 2 d.p.).

    Formula:Area of a Triangle (Sine Rule)
    A=12absinCA = \tfrac{1}{2} ab\sin C
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  18. 18.

    An object with initial velocity 1 m/s accelerates at 2.4 m/s² for 4 s. Find the distance travelled.

    Formula:Kinematics (s = ut + ½at²)
    s=ut+12at2s = ut + \tfrac{1}{2}at^2
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  19. 19.

    TSh 1,200 is invested at 3% compound interest per annum for 3 years. Find the final amount (to 2 d.p.).

    Formula:Compound Interest
    A=P(1+r100)tA = P\left(1 + \dfrac{r}{100}\right)^{t}
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  20. 20.

    A 19 kg object moves at 4 m/s. Find its kinetic energy.

    Formula:Kinetic Energy
    KE=12mv2KE = \tfrac{1}{2} m v^2
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