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South Korea · Grade 12 · Practice Sheet 24

Sheet code: SOUTH-KOREA-G12-S24 · 20 questions

Name: ______________
Date: ______________
  1. 1.

    Two masses 1,400 kg and 210 kg are 5 m apart. Find the gravitational force between them. (G = 6.674×10⁻¹¹)

    Formula:Newton’s Law of Gravitation
    F=Gm1m2r2F = G\dfrac{m_1 m_2}{r^2}
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  2. 2.

    Find the sum of the first 15 terms of an arithmetic series with first term a = 7 and common difference d = 1.

    Formula:Sum of an Arithmetic Series
    Sn=n2(2a+(n1)d)S_n = \tfrac{n}{2}\left(2a + (n-1)d\right)
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  3. 3.

    Find the gravitational potential energy of a 42 kg object raised 4 m. (g = 9.8 m/s²)

    Formula:Gravitational Potential Energy
    PE=mghPE = mgh
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  4. 4.

    A cone has base radius 12 cm and height 21 cm. Find its volume. (π ≈ 3.14159)

    Formula:Volume of a Cone
    V=13πr2hV = \tfrac{1}{3} \pi r^2 h
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  5. 5.

    Find the population standard deviation of: 13, 19, 16, 4, 2 (to 2 d.p.).

    Formula:Standard Deviation (Population)
    σ=(xxˉ)2n\sigma = \sqrt{\dfrac{\sum (x - \bar{x})^2}{n}}
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  6. 6.

    ₩2,200 is invested at 3% compound interest per annum for 4 years. Find the final amount (to 2 d.p.).

    Formula:Compound Interest
    A=P(1+r100)tA = P\left(1 + \dfrac{r}{100}\right)^{t}
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  7. 7.

    Find the population standard deviation of: 16, 6, 16, 6, 14 (to 2 d.p.).

    Formula:Standard Deviation (Population)
    σ=(xxˉ)2n\sigma = \sqrt{\dfrac{\sum (x - \bar{x})^2}{n}}
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  8. 8.

    Two masses 6,800 kg and 190 kg are 11 m apart. Find the gravitational force between them. (G = 6.674×10⁻¹¹)

    Formula:Newton’s Law of Gravitation
    F=Gm1m2r2F = G\dfrac{m_1 m_2}{r^2}
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  9. 9.

    In a triangle, a = 7, b = 14 and the included angle C = 100°. Find side c (to 2 d.p.).

    Formula:Cosine Rule
    c=a2+b22abcosCc = \sqrt{a^2 + b^2 - 2ab\cos C}
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  10. 10.

    A cone has base radius 4 cm and height 8 cm. Find its volume. (π ≈ 3.14159)

    Formula:Volume of a Cone
    V=13πr2hV = \tfrac{1}{3} \pi r^2 h
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  11. 11.

    A force of 293 N acts on an area of 3.7 m². Find the pressure.

    Formula:Pressure
    P=FAP = \dfrac{F}{A}
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  12. 12.

    An object with initial velocity 7 m/s accelerates at 2.3 m/s² for 9 s. Find the distance travelled.

    Formula:Kinematics (s = ut + ½at²)
    s=ut+12at2s = ut + \tfrac{1}{2}at^2
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  13. 13.

    Find the sum of the first 15 terms of an arithmetic series with first term a = 5 and common difference d = 8.

    Formula:Sum of an Arithmetic Series
    Sn=n2(2a+(n1)d)S_n = \tfrac{n}{2}\left(2a + (n-1)d\right)
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  14. 14.

    Two masses 3,200 kg and 210 kg are 7 m apart. Find the gravitational force between them. (G = 6.674×10⁻¹¹)

    Formula:Newton’s Law of Gravitation
    F=Gm1m2r2F = G\dfrac{m_1 m_2}{r^2}
    View formula →
  15. 15.

    Find the sum of the first 12 terms of an arithmetic series with first term a = 1 and common difference d = 4.

    Formula:Sum of an Arithmetic Series
    Sn=n2(2a+(n1)d)S_n = \tfrac{n}{2}\left(2a + (n-1)d\right)
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  16. 16.

    Find the sum of the first 8 terms of a geometric series with first term a = 7 and common ratio r = 3.

    Formula:Sum of a Geometric Series
    Sn=a(rn1)r1S_n = \dfrac{a(r^{n} - 1)}{r - 1}
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  17. 17.

    Find the gravitational potential energy of a 32 kg object raised 16 m. (g = 9.8 m/s²)

    Formula:Gravitational Potential Energy
    PE=mghPE = mgh
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  18. 18.

    A 31 kg object moves at 25 m/s. Find its kinetic energy.

    Formula:Kinetic Energy
    KE=12mv2KE = \tfrac{1}{2} m v^2
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  19. 19.

    Find the gravitational potential energy of a 30 kg object raised 34 m. (g = 9.8 m/s²)

    Formula:Gravitational Potential Energy
    PE=mghPE = mgh
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  20. 20.

    An object with initial velocity 11 m/s accelerates at 3.2 m/s² for 7 s. Find the distance travelled.

    Formula:Kinematics (s = ut + ½at²)
    s=ut+12at2s = ut + \tfrac{1}{2}at^2
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