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Saudi Arabia · Grade 12 · Practice Sheet 47

Sheet code: SAUDI-ARABIA-G12-S47 · 20 questions

Name: ______________
Date: ______________
  1. 1.

    A current of 4.4 A flows through a 41 Ω resistor. Find the voltage across it.

    Formula:Ohm's Law
    V=IRV = I R
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  2. 2.

    Find the sum of the first 7 terms of a geometric series with first term a = 6 and common ratio r = 3.

    Formula:Sum of a Geometric Series
    Sn=a(rn1)r1S_n = \dfrac{a(r^{n} - 1)}{r - 1}
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  3. 3.

    Two masses 4,500 kg and 670 kg are 7 m apart. Find the gravitational force between them. (G = 6.674×10⁻¹¹)

    Formula:Newton’s Law of Gravitation
    F=Gm1m2r2F = G\dfrac{m_1 m_2}{r^2}
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  4. 4.

    A current of 7.2 A flows through a 5 Ω resistor. Find the voltage across it.

    Formula:Ohm's Law
    V=IRV = I R
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  5. 5.

    A 17 kg object moves at 9 m/s. Find its kinetic energy.

    Formula:Kinetic Energy
    KE=12mv2KE = \tfrac{1}{2} m v^2
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  6. 6.

    SAR 3,800 is invested at 5% compound interest per annum for 5 years. Find the final amount (to 2 d.p.).

    Formula:Compound Interest
    A=P(1+r100)tA = P\left(1 + \dfrac{r}{100}\right)^{t}
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  7. 7.

    Solve using the quadratic formula: x² + 3x − 18 = 0.

    Formula:Quadratic Formula
    x=b±b24ac2ax = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}
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  8. 8.

    A force of 164 N acts on an area of 3.7 m². Find the pressure.

    Formula:Pressure
    P=FAP = \dfrac{F}{A}
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  9. 9.

    SAR 3,600 is invested at 5% compound interest per annum for 2 years. Find the final amount (to 2 d.p.).

    Formula:Compound Interest
    A=P(1+r100)tA = P\left(1 + \dfrac{r}{100}\right)^{t}
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  10. 10.

    Two masses 2,700 kg and 820 kg are 11 m apart. Find the gravitational force between them. (G = 6.674×10⁻¹¹)

    Formula:Newton’s Law of Gravitation
    F=Gm1m2r2F = G\dfrac{m_1 m_2}{r^2}
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  11. 11.

    A wave has frequency 773 Hz and wavelength 1.24 m. Find its speed.

    Formula:Wave Speed
    v=fλv = f\lambda
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  12. 12.

    Solve using the quadratic formula: x² + 1x + 0 = 0.

    Formula:Quadratic Formula
    x=b±b24ac2ax = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}
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  13. 13.

    A triangle has sides a = 14 cm and b = 10 cm with an included angle C = 45°. Find its area (to 2 d.p.).

    Formula:Area of a Triangle (Sine Rule)
    A=12absinCA = \tfrac{1}{2} ab\sin C
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  14. 14.

    A 11 kg object moves at 10 m/s. Find its kinetic energy.

    Formula:Kinetic Energy
    KE=12mv2KE = \tfrac{1}{2} m v^2
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  15. 15.

    Find the sum of the first 12 terms of an arithmetic series with first term a = 5 and common difference d = 6.

    Formula:Sum of an Arithmetic Series
    Sn=n2(2a+(n1)d)S_n = \tfrac{n}{2}\left(2a + (n-1)d\right)
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  16. 16.

    A wave has frequency 439 Hz and wavelength 2.78 m. Find its speed.

    Formula:Wave Speed
    v=fλv = f\lambda
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  17. 17.

    Find the population standard deviation of: 17, 6, 14, 3, 14 (to 2 d.p.).

    Formula:Standard Deviation (Population)
    σ=(xxˉ)2n\sigma = \sqrt{\dfrac{\sum (x - \bar{x})^2}{n}}
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  18. 18.

    Solve using the quadratic formula: x² + 11x + 30 = 0.

    Formula:Quadratic Formula
    x=b±b24ac2ax = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}
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  19. 19.

    Find the force needed to accelerate a 38 kg mass at 3 m/s².

    Formula:Newton's Second Law
    F=maF = ma
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  20. 20.

    SAR 1,200 is invested at 3% compound interest per annum for 3 years. Find the final amount (to 2 d.p.).

    Formula:Compound Interest
    A=P(1+r100)tA = P\left(1 + \dfrac{r}{100}\right)^{t}
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