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Pakistan · Class 12 · Practice Sheet 39

Sheet code: PAKISTAN-G12-S39 · 20 questions

Name: ______________
Date: ______________
  1. 1.

    A body starts at 16 m/s and accelerates at 5.5 m/s² for 5 s. Find its final velocity.

    Formula:Kinematics (v = u + at)
    v=u+atv = u + at
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  2. 2.

    In a triangle, a = 10, b = 11 and the included angle C = 40°. Find side c (to 2 d.p.).

    Formula:Cosine Rule
    c=a2+b22abcosCc = \sqrt{a^2 + b^2 - 2ab\cos C}
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  3. 3.

    A population of 1,500 grows 10% per year. Find its size after 2 years (nearest whole number).

    Formula:Exponential Growth
    N=N0(1+r)tN = N_0 (1 + r)^{t}
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  4. 4.

    Find the population standard deviation of: 18, 6, 19, 15, 14 (to 2 d.p.).

    Formula:Standard Deviation (Population)
    σ=(xxˉ)2n\sigma = \sqrt{\dfrac{\sum (x - \bar{x})^2}{n}}
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  5. 5.

    Solve using the quadratic formula: x² − 5x + 0 = 0.

    Formula:Quadratic Formula
    x=b±b24ac2ax = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}
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  6. 6.

    ₨3,900 is invested at 8% compound interest per annum for 5 years. Find the final amount (to 2 d.p.).

    Formula:Compound Interest
    A=P(1+r100)tA = P\left(1 + \dfrac{r}{100}\right)^{t}
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  7. 7.

    Find the population standard deviation of: 20, 3, 2, 2, 17 (to 2 d.p.).

    Formula:Standard Deviation (Population)
    σ=(xxˉ)2n\sigma = \sqrt{\dfrac{\sum (x - \bar{x})^2}{n}}
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  8. 8.

    A population of 7,200 grows 3% per year. Find its size after 5 years (nearest whole number).

    Formula:Exponential Growth
    N=N0(1+r)tN = N_0 (1 + r)^{t}
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  9. 9.

    Solve using the quadratic formula: x² + 0x − 9 = 0.

    Formula:Quadratic Formula
    x=b±b24ac2ax = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}
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  10. 10.

    A body starts at 6 m/s and accelerates at 4.5 m/s² for 6 s. Find its final velocity.

    Formula:Kinematics (v = u + at)
    v=u+atv = u + at
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  11. 11.

    Find the population standard deviation of: 17, 8, 15, 17, 17 (to 2 d.p.).

    Formula:Standard Deviation (Population)
    σ=(xxˉ)2n\sigma = \sqrt{\dfrac{\sum (x - \bar{x})^2}{n}}
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  12. 12.

    A force of 436 N acts on an area of 7.5 m². Find the pressure.

    Formula:Pressure
    P=FAP = \dfrac{F}{A}
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  13. 13.

    Solve using the quadratic formula: x² + 2x + 0 = 0.

    Formula:Quadratic Formula
    x=b±b24ac2ax = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}
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  14. 14.

    Two masses 2,600 kg and 760 kg are 8 m apart. Find the gravitational force between them. (G = 6.674×10⁻¹¹)

    Formula:Newton’s Law of Gravitation
    F=Gm1m2r2F = G\dfrac{m_1 m_2}{r^2}
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  15. 15.

    A device runs at 149 V drawing 2.6 A. Find its power consumption.

    Formula:Electrical Power
    P=VIP = V I
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  16. 16.

    Find the momentum of a 21 kg object moving at 19 m/s.

    Formula:Momentum
    p=mvp = mv
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  17. 17.

    Find the volume of a sphere of radius 4 cm. (π ≈ 3.14159)

    Formula:Volume of a Sphere
    V=43πr3V = \tfrac{4}{3} \pi r^3
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  18. 18.

    A force of 424 N acts on an area of 5.3 m². Find the pressure.

    Formula:Pressure
    P=FAP = \dfrac{F}{A}
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  19. 19.

    A triangle has sides a = 12 cm and b = 8 cm with an included angle C = 90°. Find its area (to 2 d.p.).

    Formula:Area of a Triangle (Sine Rule)
    A=12absinCA = \tfrac{1}{2} ab\sin C
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  20. 20.

    Find the momentum of a 33 kg object moving at 3 m/s.

    Formula:Momentum
    p=mvp = mv
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