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Norway · Grade 12 · Practice Sheet 27

Sheet code: NORWAY-G12-S27 · 20 questions

Name: ______________
Date: ______________
  1. 1.

    In a triangle, a = 16, b = 12 and the included angle C = 70°. Find side c (to 2 d.p.).

    Formula:Cosine Rule
    c=a2+b22abcosCc = \sqrt{a^2 + b^2 - 2ab\cos C}
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  2. 2.

    A body starts at 18 m/s and accelerates at 4.1 m/s² for 9 s. Find its final velocity.

    Formula:Kinematics (v = u + at)
    v=u+atv = u + at
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  3. 3.

    In a triangle, a = 8, b = 8 and the included angle C = 50°. Find side c (to 2 d.p.).

    Formula:Cosine Rule
    c=a2+b22abcosCc = \sqrt{a^2 + b^2 - 2ab\cos C}
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  4. 4.

    A device runs at 206 V drawing 6.5 A. Find its power consumption.

    Formula:Electrical Power
    P=VIP = V I
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  5. 5.

    Find the gravitational potential energy of a 39 kg object raised 34 m. (g = 9.8 m/s²)

    Formula:Gravitational Potential Energy
    PE=mghPE = mgh
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  6. 6.

    A device runs at 17 V drawing 2.8 A. Find its power consumption.

    Formula:Electrical Power
    P=VIP = V I
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  7. 7.

    A cone has base radius 6 cm and height 6 cm. Find its volume. (π ≈ 3.14159)

    Formula:Volume of a Cone
    V=13πr2hV = \tfrac{1}{3} \pi r^2 h
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  8. 8.

    A population of 2,100 grows 3% per year. Find its size after 8 years (nearest whole number).

    Formula:Exponential Growth
    N=N0(1+r)tN = N_0 (1 + r)^{t}
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  9. 9.

    A force of 104 N moves an object 33 m in the direction of the force. Find the work done.

    Formula:Work Done
    W=FdW = F d
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  10. 10.

    Find the gravitational potential energy of a 14 kg object raised 39 m. (g = 9.8 m/s²)

    Formula:Gravitational Potential Energy
    PE=mghPE = mgh
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  11. 11.

    A device runs at 215 V drawing 4 A. Find its power consumption.

    Formula:Electrical Power
    P=VIP = V I
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  12. 12.

    A current of 3 A flows through a 25 Ω resistor. Find the voltage across it.

    Formula:Ohm's Law
    V=IRV = I R
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  13. 13.

    Find the population standard deviation of: 10, 16, 16, 5, 20 (to 2 d.p.).

    Formula:Standard Deviation (Population)
    σ=(xxˉ)2n\sigma = \sqrt{\dfrac{\sum (x - \bar{x})^2}{n}}
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  14. 14.

    Two masses 3,000 kg and 860 kg are 7 m apart. Find the gravitational force between them. (G = 6.674×10⁻¹¹)

    Formula:Newton’s Law of Gravitation
    F=Gm1m2r2F = G\dfrac{m_1 m_2}{r^2}
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  15. 15.

    Solve using the quadratic formula: x² + 7x + 12 = 0.

    Formula:Quadratic Formula
    x=b±b24ac2ax = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}
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  16. 16.

    Two masses 8,000 kg and 890 kg are 15 m apart. Find the gravitational force between them. (G = 6.674×10⁻¹¹)

    Formula:Newton’s Law of Gravitation
    F=Gm1m2r2F = G\dfrac{m_1 m_2}{r^2}
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  17. 17.

    A triangle has sides a = 8 cm and b = 17 cm with an included angle C = 30°. Find its area (to 2 d.p.).

    Formula:Area of a Triangle (Sine Rule)
    A=12absinCA = \tfrac{1}{2} ab\sin C
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  18. 18.

    An object with initial velocity 12 m/s accelerates at 1.6 m/s² for 9 s. Find the distance travelled.

    Formula:Kinematics (s = ut + ½at²)
    s=ut+12at2s = ut + \tfrac{1}{2}at^2
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  19. 19.

    Solve using the quadratic formula: x² + 3x − 4 = 0.

    Formula:Quadratic Formula
    x=b±b24ac2ax = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}
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  20. 20.

    An object with initial velocity 12 m/s accelerates at 2.4 m/s² for 6 s. Find the distance travelled.

    Formula:Kinematics (s = ut + ½at²)
    s=ut+12at2s = ut + \tfrac{1}{2}at^2
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