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Kuwait · Grade 11 · Practice Sheet 25

Sheet code: KUWAIT-G11-S25 · 20 questions

Name: ______________
Date: ______________
  1. 1.

    A right-angled triangle has legs of 4 cm and 13 cm. Find the length of the hypotenuse.

    Formula:Pythagorean Theorem
    c=a2+b2c = \sqrt{a^2 + b^2}
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  2. 2.

    KD 600 is invested at 4% compound interest per annum for 4 years. Find the final amount (to 2 d.p.).

    Formula:Compound Interest
    A=P(1+r100)tA = P\left(1 + \dfrac{r}{100}\right)^{t}
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  3. 3.

    Find the sum of the first 18 terms of an arithmetic series with first term a = 3 and common difference d = 5.

    Formula:Sum of an Arithmetic Series
    Sn=n2(2a+(n1)d)S_n = \tfrac{n}{2}\left(2a + (n-1)d\right)
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  4. 4.

    Solve using the quadratic formula: x² − 5x + 6 = 0.

    Formula:Quadratic Formula
    x=b±b24ac2ax = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}
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  5. 5.

    Find the volume of a sphere of radius 12 cm. (π ≈ 3.14159)

    Formula:Volume of a Sphere
    V=43πr3V = \tfrac{4}{3} \pi r^3
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  6. 6.

    A population of 8,700 grows 3% per year. Find its size after 7 years (nearest whole number).

    Formula:Exponential Growth
    N=N0(1+r)tN = N_0 (1 + r)^{t}
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  7. 7.

    A force of 212 N acts on an area of 1.5 m². Find the pressure.

    Formula:Pressure
    P=FAP = \dfrac{F}{A}
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  8. 8.

    Find the sum of the first 7 terms of a geometric series with first term a = 6 and common ratio r = 4.

    Formula:Sum of a Geometric Series
    Sn=a(rn1)r1S_n = \dfrac{a(r^{n} - 1)}{r - 1}
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  9. 9.

    A right-angled triangle has legs of 16 cm and 15 cm. Find the length of the hypotenuse.

    Formula:Pythagorean Theorem
    c=a2+b2c = \sqrt{a^2 + b^2}
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  10. 10.

    Solve using the quadratic formula: x² + 3x + 2 = 0.

    Formula:Quadratic Formula
    x=b±b24ac2ax = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}
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  11. 11.

    A cone has base radius 9 cm and height 21 cm. Find its volume. (π ≈ 3.14159)

    Formula:Volume of a Cone
    V=13πr2hV = \tfrac{1}{3} \pi r^2 h
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  12. 12.

    Two masses 6,800 kg and 510 kg are 11 m apart. Find the gravitational force between them. (G = 6.674×10⁻¹¹)

    Formula:Newton’s Law of Gravitation
    F=Gm1m2r2F = G\dfrac{m_1 m_2}{r^2}
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  13. 13.

    Find the sum of the first 8 terms of a geometric series with first term a = 2 and common ratio r = 3.

    Formula:Sum of a Geometric Series
    Sn=a(rn1)r1S_n = \dfrac{a(r^{n} - 1)}{r - 1}
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  14. 14.

    Solve using the quadratic formula: x² + 3x − 4 = 0.

    Formula:Quadratic Formula
    x=b±b24ac2ax = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}
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  15. 15.

    KD 1,900 is invested at 6% compound interest per annum for 4 years. Find the final amount (to 2 d.p.).

    Formula:Compound Interest
    A=P(1+r100)tA = P\left(1 + \dfrac{r}{100}\right)^{t}
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  16. 16.

    Two masses 5,400 kg and 530 kg are 4 m apart. Find the gravitational force between them. (G = 6.674×10⁻¹¹)

    Formula:Newton’s Law of Gravitation
    F=Gm1m2r2F = G\dfrac{m_1 m_2}{r^2}
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  17. 17.

    A force of 68 N moves an object 20 m in the direction of the force. Find the work done.

    Formula:Work Done
    W=FdW = F d
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  18. 18.

    A cylinder has radius 5 cm and height 13 cm. Find its volume. (π ≈ 3.14159)

    Formula:Volume of a Cylinder
    V=πr2hV = \pi r^2 h
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  19. 19.

    Find the force needed to accelerate a 24 kg mass at 2.8 m/s².

    Formula:Newton's Second Law
    F=maF = ma
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  20. 20.

    Find the gravitational potential energy of a 49 kg object raised 27 m. (g = 9.8 m/s²)

    Formula:Gravitational Potential Energy
    PE=mghPE = mgh
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