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Japan · Grade 11 · Practice Sheet 30

Sheet code: JAPAN-G11-S30 · 20 questions

Name: ______________
Date: ______________
  1. 1.

    An object with initial velocity 10 m/s accelerates at 4.2 m/s² for 8 s. Find the distance travelled.

    Formula:Kinematics (s = ut + ½at²)
    s=ut+12at2s = ut + \tfrac{1}{2}at^2
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  2. 2.

    A current of 4.1 A flows through a 36 Ω resistor. Find the voltage across it.

    Formula:Ohm's Law
    V=IRV = I R
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  3. 3.

    A 40 kg object moves at 3 m/s. Find its kinetic energy.

    Formula:Kinetic Energy
    KE=12mv2KE = \tfrac{1}{2} m v^2
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  4. 4.

    A population of 4,400 grows 2% per year. Find its size after 2 years (nearest whole number).

    Formula:Exponential Growth
    N=N0(1+r)tN = N_0 (1 + r)^{t}
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  5. 5.

    Solve using the quadratic formula: x² + 7x + 6 = 0.

    Formula:Quadratic Formula
    x=b±b24ac2ax = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}
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  6. 6.

    A cylinder has radius 10 cm and height 12 cm. Find its volume. (π ≈ 3.14159)

    Formula:Volume of a Cylinder
    V=πr2hV = \pi r^2 h
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  7. 7.

    Find the volume of a sphere of radius 9 cm. (π ≈ 3.14159)

    Formula:Volume of a Sphere
    V=43πr3V = \tfrac{4}{3} \pi r^3
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  8. 8.

    Solve using the quadratic formula: x² − 4x − 12 = 0.

    Formula:Quadratic Formula
    x=b±b24ac2ax = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}
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  9. 9.

    A body starts at 18 m/s and accelerates at 4.5 m/s² for 7 s. Find its final velocity.

    Formula:Kinematics (v = u + at)
    v=u+atv = u + at
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  10. 10.

    ¥2,500 is invested at 3% compound interest per annum for 4 years. Find the final amount (to 2 d.p.).

    Formula:Compound Interest
    A=P(1+r100)tA = P\left(1 + \dfrac{r}{100}\right)^{t}
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  11. 11.

    A right-angled triangle has legs of 19 cm and 7 cm. Find the length of the hypotenuse.

    Formula:Pythagorean Theorem
    c=a2+b2c = \sqrt{a^2 + b^2}
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  12. 12.

    A cone has base radius 12 cm and height 13 cm. Find its volume. (π ≈ 3.14159)

    Formula:Volume of a Cone
    V=13πr2hV = \tfrac{1}{3} \pi r^2 h
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  13. 13.

    Two masses 2,700 kg and 470 kg are 18 m apart. Find the gravitational force between them. (G = 6.674×10⁻¹¹)

    Formula:Newton’s Law of Gravitation
    F=Gm1m2r2F = G\dfrac{m_1 m_2}{r^2}
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  14. 14.

    A triangle has sides a = 8 cm and b = 11 cm with an included angle C = 120°. Find its area (to 2 d.p.).

    Formula:Area of a Triangle (Sine Rule)
    A=12absinCA = \tfrac{1}{2} ab\sin C
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  15. 15.

    Two masses 2,800 kg and 180 kg are 13 m apart. Find the gravitational force between them. (G = 6.674×10⁻¹¹)

    Formula:Newton’s Law of Gravitation
    F=Gm1m2r2F = G\dfrac{m_1 m_2}{r^2}
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  16. 16.

    A cylinder has radius 4 cm and height 18 cm. Find its volume. (π ≈ 3.14159)

    Formula:Volume of a Cylinder
    V=πr2hV = \pi r^2 h
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  17. 17.

    Two masses 2,900 kg and 800 kg are 18 m apart. Find the gravitational force between them. (G = 6.674×10⁻¹¹)

    Formula:Newton’s Law of Gravitation
    F=Gm1m2r2F = G\dfrac{m_1 m_2}{r^2}
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  18. 18.

    A force of 178 N acts on an area of 6 m². Find the pressure.

    Formula:Pressure
    P=FAP = \dfrac{F}{A}
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  19. 19.

    Find the population standard deviation of: 16, 18, 18, 7, 20 (to 2 d.p.).

    Formula:Standard Deviation (Population)
    σ=(xxˉ)2n\sigma = \sqrt{\dfrac{\sum (x - \bar{x})^2}{n}}
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  20. 20.

    A population of 1,600 grows 10% per year. Find its size after 3 years (nearest whole number).

    Formula:Exponential Growth
    N=N0(1+r)tN = N_0 (1 + r)^{t}
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