India · Class 12 · Practice Sheet 34
Sheet code: INDIA-G12-S34 · 20 questions
- 1.
Solve using the quadratic formula: x² + 3x − 4 = 0.
- 2.
A body starts at 17 m/s and accelerates at 4.7 m/s² for 3 s. Find its final velocity.
- 3.
Find the gravitational potential energy of a 3 kg object raised 16 m. (g = 9.8 m/s²)
- 4.
Find the sum of the first 18 terms of an arithmetic series with first term a = 10 and common difference d = 6.
- 5.
₹2,400 is invested at 5% compound interest per annum for 2 years. Find the final amount (to 2 d.p.).
- 6.
A population of 8,500 grows 10% per year. Find its size after 2 years (nearest whole number).
- 7.
A force of 137 N acts on an area of 0.8 m². Find the pressure.
- 8.
Find the gravitational potential energy of a 4 kg object raised 27 m. (g = 9.8 m/s²)
- 9.
₹600 is invested at 8% compound interest per annum for 5 years. Find the final amount (to 2 d.p.).
- 10.
Find the sum of the first 14 terms of an arithmetic series with first term a = 2 and common difference d = 3.
- 11.
An object with initial velocity 2 m/s accelerates at 4.3 m/s² for 8 s. Find the distance travelled.
- 12.
Find the population standard deviation of: 15, 7, 10, 2, 6 (to 2 d.p.).
- 13.
A wave has frequency 752 Hz and wavelength 3 m. Find its speed.
- 14.
In a triangle, a = 11, b = 14 and the included angle C = 100°. Find side c (to 2 d.p.).
- 15.
A force of 89 N moves an object 24 m in the direction of the force. Find the work done.
- 16.
Two masses 8,700 kg and 730 kg are 8 m apart. Find the gravitational force between them. (G = 6.674×10⁻¹¹)
- 17.
A cone has base radius 5 cm and height 11 cm. Find its volume. (π ≈ 3.14159)
- 18.
Two masses 8,900 kg and 590 kg are 11 m apart. Find the gravitational force between them. (G = 6.674×10⁻¹¹)
- 19.
Find the sum of the first 19 terms of an arithmetic series with first term a = 1 and common difference d = 8.
- 20.
Solve using the quadratic formula: x² − 3x − 10 = 0.
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