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India · Class 12 · Practice Sheet 34

Sheet code: INDIA-G12-S34 · 20 questions

Name: ______________
Date: ______________
  1. 1.

    Solve using the quadratic formula: x² + 3x − 4 = 0.

    Formula:Quadratic Formula
    x=b±b24ac2ax = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}
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  2. 2.

    A body starts at 17 m/s and accelerates at 4.7 m/s² for 3 s. Find its final velocity.

    Formula:Kinematics (v = u + at)
    v=u+atv = u + at
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  3. 3.

    Find the gravitational potential energy of a 3 kg object raised 16 m. (g = 9.8 m/s²)

    Formula:Gravitational Potential Energy
    PE=mghPE = mgh
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  4. 4.

    Find the sum of the first 18 terms of an arithmetic series with first term a = 10 and common difference d = 6.

    Formula:Sum of an Arithmetic Series
    Sn=n2(2a+(n1)d)S_n = \tfrac{n}{2}\left(2a + (n-1)d\right)
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  5. 5.

    ₹2,400 is invested at 5% compound interest per annum for 2 years. Find the final amount (to 2 d.p.).

    Formula:Compound Interest
    A=P(1+r100)tA = P\left(1 + \dfrac{r}{100}\right)^{t}
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  6. 6.

    A population of 8,500 grows 10% per year. Find its size after 2 years (nearest whole number).

    Formula:Exponential Growth
    N=N0(1+r)tN = N_0 (1 + r)^{t}
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  7. 7.

    A force of 137 N acts on an area of 0.8 m². Find the pressure.

    Formula:Pressure
    P=FAP = \dfrac{F}{A}
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  8. 8.

    Find the gravitational potential energy of a 4 kg object raised 27 m. (g = 9.8 m/s²)

    Formula:Gravitational Potential Energy
    PE=mghPE = mgh
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  9. 9.

    ₹600 is invested at 8% compound interest per annum for 5 years. Find the final amount (to 2 d.p.).

    Formula:Compound Interest
    A=P(1+r100)tA = P\left(1 + \dfrac{r}{100}\right)^{t}
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  10. 10.

    Find the sum of the first 14 terms of an arithmetic series with first term a = 2 and common difference d = 3.

    Formula:Sum of an Arithmetic Series
    Sn=n2(2a+(n1)d)S_n = \tfrac{n}{2}\left(2a + (n-1)d\right)
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  11. 11.

    An object with initial velocity 2 m/s accelerates at 4.3 m/s² for 8 s. Find the distance travelled.

    Formula:Kinematics (s = ut + ½at²)
    s=ut+12at2s = ut + \tfrac{1}{2}at^2
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  12. 12.

    Find the population standard deviation of: 15, 7, 10, 2, 6 (to 2 d.p.).

    Formula:Standard Deviation (Population)
    σ=(xxˉ)2n\sigma = \sqrt{\dfrac{\sum (x - \bar{x})^2}{n}}
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  13. 13.

    A wave has frequency 752 Hz and wavelength 3 m. Find its speed.

    Formula:Wave Speed
    v=fλv = f\lambda
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  14. 14.

    In a triangle, a = 11, b = 14 and the included angle C = 100°. Find side c (to 2 d.p.).

    Formula:Cosine Rule
    c=a2+b22abcosCc = \sqrt{a^2 + b^2 - 2ab\cos C}
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  15. 15.

    A force of 89 N moves an object 24 m in the direction of the force. Find the work done.

    Formula:Work Done
    W=FdW = F d
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  16. 16.

    Two masses 8,700 kg and 730 kg are 8 m apart. Find the gravitational force between them. (G = 6.674×10⁻¹¹)

    Formula:Newton’s Law of Gravitation
    F=Gm1m2r2F = G\dfrac{m_1 m_2}{r^2}
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  17. 17.

    A cone has base radius 5 cm and height 11 cm. Find its volume. (π ≈ 3.14159)

    Formula:Volume of a Cone
    V=13πr2hV = \tfrac{1}{3} \pi r^2 h
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  18. 18.

    Two masses 8,900 kg and 590 kg are 11 m apart. Find the gravitational force between them. (G = 6.674×10⁻¹¹)

    Formula:Newton’s Law of Gravitation
    F=Gm1m2r2F = G\dfrac{m_1 m_2}{r^2}
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  19. 19.

    Find the sum of the first 19 terms of an arithmetic series with first term a = 1 and common difference d = 8.

    Formula:Sum of an Arithmetic Series
    Sn=n2(2a+(n1)d)S_n = \tfrac{n}{2}\left(2a + (n-1)d\right)
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  20. 20.

    Solve using the quadratic formula: x² − 3x − 10 = 0.

    Formula:Quadratic Formula
    x=b±b24ac2ax = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}
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