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Bangladesh · Class 12 · Practice Sheet 5

Sheet code: BANGLADESH-G12-S05 · 20 questions

Name: ______________
Date: ______________
  1. 1.

    A cone has base radius 7 cm and height 24 cm. Find its volume. (π ≈ 3.14159)

    Formula:Volume of a Cone
    V=13πr2hV = \tfrac{1}{3} \pi r^2 h
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  2. 2.

    Solve using the quadratic formula: x² − 10x + 24 = 0.

    Formula:Quadratic Formula
    x=b±b24ac2ax = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}
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  3. 3.

    A triangle has sides a = 12 cm and b = 10 cm with an included angle C = 45°. Find its area (to 2 d.p.).

    Formula:Area of a Triangle (Sine Rule)
    A=12absinCA = \tfrac{1}{2} ab\sin C
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  4. 4.

    A wave has frequency 567 Hz and wavelength 2.68 m. Find its speed.

    Formula:Wave Speed
    v=fλv = f\lambda
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  5. 5.

    A population of 5,200 grows 8% per year. Find its size after 5 years (nearest whole number).

    Formula:Exponential Growth
    N=N0(1+r)tN = N_0 (1 + r)^{t}
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  6. 6.

    Find the gravitational potential energy of a 40 kg object raised 26 m. (g = 9.8 m/s²)

    Formula:Gravitational Potential Energy
    PE=mghPE = mgh
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  7. 7.

    Two masses 2,200 kg and 150 kg are 18 m apart. Find the gravitational force between them. (G = 6.674×10⁻¹¹)

    Formula:Newton’s Law of Gravitation
    F=Gm1m2r2F = G\dfrac{m_1 m_2}{r^2}
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  8. 8.

    In a triangle, a = 16, b = 9 and the included angle C = 110°. Find side c (to 2 d.p.).

    Formula:Cosine Rule
    c=a2+b22abcosCc = \sqrt{a^2 + b^2 - 2ab\cos C}
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  9. 9.

    Solve using the quadratic formula: x² + 0x − 4 = 0.

    Formula:Quadratic Formula
    x=b±b24ac2ax = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}
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  10. 10.

    A body starts at 1 m/s and accelerates at 5.5 m/s² for 10 s. Find its final velocity.

    Formula:Kinematics (v = u + at)
    v=u+atv = u + at
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  11. 11.

    Find the population standard deviation of: 15, 3, 8, 16, 17 (to 2 d.p.).

    Formula:Standard Deviation (Population)
    σ=(xxˉ)2n\sigma = \sqrt{\dfrac{\sum (x - \bar{x})^2}{n}}
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  12. 12.

    Two masses 5,400 kg and 500 kg are 11 m apart. Find the gravitational force between them. (G = 6.674×10⁻¹¹)

    Formula:Newton’s Law of Gravitation
    F=Gm1m2r2F = G\dfrac{m_1 m_2}{r^2}
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  13. 13.

    Solve using the quadratic formula: x² + 1x − 2 = 0.

    Formula:Quadratic Formula
    x=b±b24ac2ax = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}
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  14. 14.

    Find the volume of a sphere of radius 6 cm. (π ≈ 3.14159)

    Formula:Volume of a Sphere
    V=43πr3V = \tfrac{4}{3} \pi r^3
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  15. 15.

    Find the gravitational potential energy of a 3 kg object raised 13 m. (g = 9.8 m/s²)

    Formula:Gravitational Potential Energy
    PE=mghPE = mgh
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  16. 16.

    Find the force needed to accelerate a 13 kg mass at 7.6 m/s².

    Formula:Newton's Second Law
    F=maF = ma
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  17. 17.

    A cone has base radius 9 cm and height 14 cm. Find its volume. (π ≈ 3.14159)

    Formula:Volume of a Cone
    V=13πr2hV = \tfrac{1}{3} \pi r^2 h
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  18. 18.

    A force of 150 N acts on an area of 1.9 m². Find the pressure.

    Formula:Pressure
    P=FAP = \dfrac{F}{A}
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  19. 19.

    Find the volume of a sphere of radius 11 cm. (π ≈ 3.14159)

    Formula:Volume of a Sphere
    V=43πr3V = \tfrac{4}{3} \pi r^3
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  20. 20.

    A 2 kg object moves at 4 m/s. Find its kinetic energy.

    Formula:Kinetic Energy
    KE=12mv2KE = \tfrac{1}{2} m v^2
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