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Austria · Klasse 12 · Practice Sheet 21

Sheet code: AUSTRIA-G12-S21 · 20 questions

Name: ______________
Date: ______________
  1. 1.

    Find the sum of the first 12 terms of an arithmetic series with first term a = 10 and common difference d = 7.

    Formula:Sum of an Arithmetic Series
    Sn=n2(2a+(n1)d)S_n = \tfrac{n}{2}\left(2a + (n-1)d\right)
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  2. 2.

    Find the force needed to accelerate a 44 kg mass at 1.5 m/s².

    Formula:Newton's Second Law
    F=maF = ma
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  3. 3.

    Find the sum of the first 17 terms of an arithmetic series with first term a = 5 and common difference d = 5.

    Formula:Sum of an Arithmetic Series
    Sn=n2(2a+(n1)d)S_n = \tfrac{n}{2}\left(2a + (n-1)d\right)
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  4. 4.

    Find the momentum of a 12 kg object moving at 2 m/s.

    Formula:Momentum
    p=mvp = mv
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  5. 5.

    A population of 6,300 grows 10% per year. Find its size after 4 years (nearest whole number).

    Formula:Exponential Growth
    N=N0(1+r)tN = N_0 (1 + r)^{t}
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  6. 6.

    Find the volume of a sphere of radius 10 cm. (π ≈ 3.14159)

    Formula:Volume of a Sphere
    V=43πr3V = \tfrac{4}{3} \pi r^3
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  7. 7.

    €900 is invested at 6% compound interest per annum for 4 years. Find the final amount (to 2 d.p.).

    Formula:Compound Interest
    A=P(1+r100)tA = P\left(1 + \dfrac{r}{100}\right)^{t}
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  8. 8.

    Two masses 7,100 kg and 430 kg are 14 m apart. Find the gravitational force between them. (G = 6.674×10⁻¹¹)

    Formula:Newton’s Law of Gravitation
    F=Gm1m2r2F = G\dfrac{m_1 m_2}{r^2}
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  9. 9.

    A cone has base radius 7 cm and height 17 cm. Find its volume. (π ≈ 3.14159)

    Formula:Volume of a Cone
    V=13πr2hV = \tfrac{1}{3} \pi r^2 h
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  10. 10.

    Find the volume of a sphere of radius 8 cm. (π ≈ 3.14159)

    Formula:Volume of a Sphere
    V=43πr3V = \tfrac{4}{3} \pi r^3
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  11. 11.

    Two masses 6,800 kg and 760 kg are 14 m apart. Find the gravitational force between them. (G = 6.674×10⁻¹¹)

    Formula:Newton’s Law of Gravitation
    F=Gm1m2r2F = G\dfrac{m_1 m_2}{r^2}
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  12. 12.

    Find the sum of the first 6 terms of an arithmetic series with first term a = 4 and common difference d = 3.

    Formula:Sum of an Arithmetic Series
    Sn=n2(2a+(n1)d)S_n = \tfrac{n}{2}\left(2a + (n-1)d\right)
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  13. 13.

    Solve using the quadratic formula: x² + 2x − 15 = 0.

    Formula:Quadratic Formula
    x=b±b24ac2ax = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}
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  14. 14.

    A wave has frequency 272 Hz and wavelength 1.79 m. Find its speed.

    Formula:Wave Speed
    v=fλv = f\lambda
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  15. 15.

    Two masses 8,800 kg and 520 kg are 17 m apart. Find the gravitational force between them. (G = 6.674×10⁻¹¹)

    Formula:Newton’s Law of Gravitation
    F=Gm1m2r2F = G\dfrac{m_1 m_2}{r^2}
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  16. 16.

    Find the gravitational potential energy of a 12 kg object raised 8 m. (g = 9.8 m/s²)

    Formula:Gravitational Potential Energy
    PE=mghPE = mgh
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  17. 17.

    A wave has frequency 236 Hz and wavelength 3.18 m. Find its speed.

    Formula:Wave Speed
    v=fλv = f\lambda
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  18. 18.

    An object with initial velocity 10 m/s accelerates at 1.2 m/s² for 2 s. Find the distance travelled.

    Formula:Kinematics (s = ut + ½at²)
    s=ut+12at2s = ut + \tfrac{1}{2}at^2
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  19. 19.

    In a triangle, a = 11, b = 17 and the included angle C = 50°. Find side c (to 2 d.p.).

    Formula:Cosine Rule
    c=a2+b22abcosCc = \sqrt{a^2 + b^2 - 2ab\cos C}
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  20. 20.

    A cone has base radius 4 cm and height 7 cm. Find its volume. (π ≈ 3.14159)

    Formula:Volume of a Cone
    V=13πr2hV = \tfrac{1}{3} \pi r^2 h
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