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Wind Turbine Power

Power a wind turbine extracts, rising with the cube of wind speed.

Formula

P=12ρAv3CpP = \tfrac{1}{2}\rho A v^3 C_p

Variables

PPower (W)
ρAir density (kg/m³)
ARotor swept area (m²)
vWind speed (m/s)
C_pPower coefficient

Example

ρ=1.2, A=8000, v=12, C_p=0.4: P ≈ 3.3 MW

How it works

This formula estimates the mechanical power available from wind as it passes through the area swept by a turbine rotor. It comes from the kinetic energy carried by moving air: the mass of air flowing each second through area A is proportional to ρAv, and each kilogram carries kinetic energy proportional to v², so the power available scales as ρAv³. The factor C_p accounts for the fact that no real turbine can capture all of that energy; it depends on blade design, tip-speed ratio, and operating conditions.

When to use it

Use this when estimating the output of a wind turbine from local wind conditions and rotor size, or when comparing different turbine designs. It is especially useful in renewable-energy sizing, site assessment, and checking whether a quoted turbine power rating is plausible at a given wind speed.

Worked example, step by step

Given: ρ = 1.225 kg/m³, A = 5027 m², v = 10.5 m/s, C_p = 0.38 Step 1: Cube the wind speed: v^3 = 10.5^3 = 1157.625 Step 2: Multiply by air density and area: 0.5 × 1.225 × 5027 = 3070.4125 Step 3: Multiply by v^3: 3070.4125 × 1157.625 = 3,553,349.0 Step 4: Apply the power coefficient: P = 3,553,349.0 × 0.38 = 1,350,272.6 W Final answer: P ≈ 1.35 × 10^6 W ≈ 1.35 MW

Common mistakes to avoid

  • Using the rotor radius instead of the swept area A = πr²
  • Forgetting that wind speed is cubed, which makes small speed changes have a large effect
  • Treating C_p as 1; real turbines are limited and usually have C_p well below 0.6

Did You Know?

Because power scales with v³, a site with 25% more wind yields roughly double the energy.

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Reviewed & maintained by the FormulaWon editorial teamLast reviewed September 2026