Physics Laws & Theorems
Intermediate

Lens Maker's / Thin Lens

Relates focal length to object and image distances for a thin lens.

Formula

1f=1v−1u\frac{1}{f} = \frac{1}{v} - \frac{1}{u}

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Variables

fFocal length
vImage distance
uObject distance

Example

An object 30 cm from a 10 cm-focal-length lens forms an image at 15 cm.

How it works

This formula connects the three key distances in a thin lens setup: the focal length, the object distance, and the image distance. It comes from the geometry of how a converging or diverging lens bends rays so they meet, or appear to meet, at an image point. The signs matter because real and virtual images lie on opposite sides of the lens, so the equation is really a compact way to track lens direction and image formation.

When to use it

Use it when you know two of the three lens quantities and need the third, especially in ray-diagram problems or simple optics calculations. It is most useful for thin lenses in school physics, camera/eyeglass-style lens questions, and image-position predictions.

Worked example, step by step

A converging lens has focal length f = 15 cm. An object is placed 30 cm from the lens. Find the image distance v. Step 1: Write the formula: 1/f = 1/v - 1/u Step 2: Substitute the values: 1/15 = 1/v - 1/30 Step 3: Add 1/30 to both sides: 1/v = 1/15 + 1/30 Step 4: Find a common denominator: 1/v = 2/30 + 1/30 = 3/30 Step 5: Simplify: 1/v = 1/10 Step 6: Invert both sides: v = 10 cm Final answer: the image forms 10 cm from the lens.

Common mistakes to avoid

  • Using the wrong sign for u or v when the image is virtual or the object is on the opposite side of the lens
  • Mixing up focal length with object distance and substituting the wrong quantity into f
  • Forgetting to keep units consistent, such as combining cm and m in the same calculation

Did You Know?

This equation lets opticians grind lenses to precise focal lengths for glasses and cameras.

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Reviewed & maintained by the FormulaWon editorial teamLast reviewed September 2026