Physics Laws & Theorems
Intermediate

Archimedes' Principle

Buoyant force equals the weight of fluid displaced.

Formula

Fb=ρgVF_b = \rho g V

Variables

\rhoFluid density
gGravity
VDisplaced volume

Example

A 1000 cm³ object submerged in water feels an upward buoyant force of about 9.8 N.

How it works

When an object is placed in a fluid, the pressure is greater at deeper points, so the bottom of the object is pushed up more strongly than the top is pushed down. That pressure difference adds up to a net upward force, and for a fully or partially submerged object it equals the weight of the fluid that the object displaces. The formula F_b = rho g V shows that this buoyant force depends on the fluid’s density, gravity, and the volume of fluid displaced, not directly on the object’s own mass.

When to use it

Use this formula whenever you need the upward buoyant force on an object in a liquid or gas, such as finding whether something will float, estimating apparent weight underwater, or calculating how much lift a submerged or floating body gets. It is also useful in density and displacement problems in ship design, hydrometers, and lab measurements.

Worked example, step by step

A small metal block displaces 0.0035 m^3 of fresh water when fully submerged. Find the buoyant force on it. Step 1: Write the formula: F_b = rho g V Step 2: Substitute the values: F_b = (1000 kg/m^3)(9.8 m/s^2)(0.0035 m^3) Step 3: Multiply the numbers: F_b = 34.3 N Step 4: State the answer: the buoyant force is 34.3 N upward.

Common mistakes to avoid

  • Using the object’s own volume instead of the displaced fluid volume
  • Forgetting to use the density of the fluid, not the density of the object
  • Mixing units, such as using cm^3 with kg/m^3 without converting to m^3

Did You Know?

Archimedes reportedly leapt from his bath shouting "Eureka!" upon discovering buoyancy.

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Reviewed & maintained by the FormulaWon editorial teamLast reviewed September 2026