Photography & Imaging
Intermediate

Lens Magnification

Image magnification from focal length and subject distance.

Formula

M=fs−fM = \frac{f}{s - f}

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Variables

MMagnification
fFocal length (mm)
sSubject distance (mm)

Example

f=100 mm, s=300 mm: M = 100/200 = 0.5×

How it works

This formula tells you how large a subject’s image forms on the sensor relative to the real subject size when using a thin lens. It comes from the standard lens geometry: as the subject moves closer to the focal length, the image distance grows quickly, so magnification rises sharply; if the subject is far away compared with the focal length, magnification becomes small. The quantity is dimensionless, and the result is often used as a size ratio rather than a percentage.

When to use it

Use this when you need to estimate how big a subject will appear on a sensor or film at a given shooting distance, especially in close-up, macro, or product photography. It is also useful for comparing lenses or planning framing before taking the shot.

Worked example, step by step

Given: f = 85 mm, s = 425 mm Step 1: Substitute into the formula M = f / (s - f) M = 85 / (425 - 85) Step 2: Calculate the denominator M = 85 / 340 Step 3: Divide M = 0.25 Final answer: The lens magnification is 0.25×, meaning the image on the sensor is one-quarter of the subject's real size.

Common mistakes to avoid

  • Using subject distance in metres without converting it to millimetres first
  • Using the formula when the subject distance is measured from the sensor plane but then mixing it with lens-to-subject distance instead
  • Forgetting that the result is a ratio, so 0.5 means 0.5× magnification, not 50×

Did You Know?

True macro lenses reach 1:1 magnification — the subject is projected life-size onto the sensor.

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Reviewed & maintained by the FormulaWon editorial teamLast reviewed September 2026