Photography & Imaging
Intermediate

Angle of View

Field of view from sensor size and focal length.

Formula

α=2arctan⁡ ⁣(d2f)\alpha = 2\arctan\!\left(\frac{d}{2f}\right)

Variables

αAngle of view
dSensor dimension (mm)
fFocal length (mm)

Example

d=36 mm, f=50 mm: α = 2 arctan(0.36) ≈ 39.6°

How it works

This formula gives the angular width of the scene that fits across a camera sensor for a given focal length. It comes from simple pinhole-camera geometry: the sensor half-width and focal length form a right triangle, so half the angle of view is arctan(d/2f), and doubling it gives the full angle. Larger sensors increase the angle of view, while longer focal lengths narrow it.

When to use it

Use this when you want to predict how wide a lens will frame a scene on a specific sensor, such as choosing between wide-angle, standard, and telephoto options. It is also useful for comparing cameras with different sensor sizes or for matching the field of view between systems.

Worked example, step by step

Given sensor dimension d = 24 mm and focal length f = 85 mm Step 1: Substitute into the formula α = 2 arctan(d / 2f) α = 2 arctan(24 / (2 × 85)) Step 2: Simplify the fraction α = 2 arctan(24 / 170) α = 2 arctan(0.141176...) Step 3: Evaluate the arctangent arctan(0.141176...) ≈ 8.03° Step 4: Double it α ≈ 2 × 8.03° = 16.06° Final answer: α ≈ 16.1°

Common mistakes to avoid

  • Using the sensor diagonal when the formula calls for a specific sensor dimension like width or height
  • Forgetting to divide the sensor dimension by 2 before taking arctan
  • Mixing up degrees and radians when reporting the final angle

Did You Know?

A 50 mm lens on full-frame roughly matches the human eye's natural angle of view — hence 'nifty fifty'.

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Reviewed & maintained by the FormulaWon editorial teamLast reviewed September 2026