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Log Mean Temperature Difference

Effective average temperature gap driving heat across an exchanger.

Formula

LMTD=ΔT1−ΔT2ln⁡(ΔT1/ΔT2)LMTD = \frac{\Delta T_1 - \Delta T_2}{\ln(\Delta T_1 / \Delta T_2)}

Variables

LMTDMean temp difference
\Delta T_1Gap at one end
\Delta T_2Gap at other end

Example

ΔT₁=40, ΔT₂=20: LMTD = 20/ln2 ≈ 28.9

How it works

In a heat exchanger, the temperature difference between the hot and cold streams usually changes from one end to the other, so a simple arithmetic average can misrepresent the true driving force for heat transfer. The log mean temperature difference (LMTD) is the mathematically correct average that comes from integrating the local temperature difference along the exchanger length under steady flow assumptions. It gives the single constant temperature gap that would transfer the same total heat as the real, varying profile.

When to use it

Use this formula when analyzing or sizing heat exchangers such as condensers, evaporators, shell-and-tube units, or plate exchangers. It is especially useful whenever the inlet and outlet temperatures of the two fluid streams are known and you need the effective temperature driving force for heat transfer calculations.

Worked example, step by step

Given: ΔT₁ = 75°C, ΔT₂ = 25°C Step 1: Substitute into the LMTD formula LMTD = (ΔT₁ - ΔT₂) / ln(ΔT₁ / ΔT₂) Step 2: Compute the numerator 75 - 25 = 50 Step 3: Compute the ratio inside the log 75 / 25 = 3 Step 4: Take the natural log ln(3) ≈ 1.0986 Step 5: Divide LMTD = 50 / 1.0986 ≈ 45.5°C Final answer: LMTD ≈ 45.5°C

Common mistakes to avoid

  • Using log base 10 instead of the natural logarithm
  • Swapping ΔT₁ and ΔT₂ without keeping the order consistent
  • Using this formula when one temperature difference is zero or negative without checking the exchanger arrangement and sign convention

Did You Know?

LMTD is used because the temperature difference along a heat exchanger changes non-linearly.

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Reviewed & maintained by the FormulaWon editorial teamLast reviewed September 2026