HVAC & Refrigeration
Intermediate

Latent Heat Load

Heat absorbed or released when moisture condenses or evaporates — the hidden load air conditioners fight.

Formula

Q=mLQ = m L

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Variables

QHeat (J)
mMass of water (kg)
LLatent heat (J/kg)

Example

0.5 kg vapour, L=2.26×10⁶: Q = 1.13 MJ

How it works

This formula tells you how much energy is involved when a substance changes phase without changing temperature, such as water vapour condensing into liquid on a cooling coil or liquid water evaporating into air. The mass of water involved is multiplied by the latent heat because each kilogram needs the same fixed amount of energy to complete that phase change. In HVAC systems, this is the part of the cooling load that removes moisture from air, not just sensible heat that changes air temperature.

When to use it

Use this when calculating the moisture-related load in air conditioning, refrigeration, dehumidification, or condensation problems. It is especially useful whenever water is changing state, such as condensation on evaporator coils or evaporation from a humidifier.

Worked example, step by step

A dehumidifier condenses 0.8 kg of water from indoor air. Use the latent heat of vaporization/condensation for water, L = 2.26 × 10^6 J/kg. Q = mL Q = 0.8 × 2.26 × 10^6 Q = 1.808 × 10^6 J Q = 1.81 MJ So, the dehumidifier must remove 1.81 MJ of latent heat from the air.

Common mistakes to avoid

  • Using the wrong latent heat value for the phase change involved
  • Forgetting that Q is in joules, so kg and J/kg must be used consistently
  • Applying this formula to temperature changes instead of phase changes

Did You Know?

Removing humidity often uses more energy than cooling the air itself in tropical climates.

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Reviewed & maintained by the FormulaWon editorial teamLast reviewed September 2026