HVAC & Refrigeration
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Humidity Ratio

Mass of water vapour per unit mass of dry air.

Formula

w=0.622pvppvw = 0.622 \frac{p_v}{p - p_v}

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Variables

wHumidity ratio (kg/kg)
p_vVapour pressure (Pa)
pTotal pressure (Pa)

Example

p_v=1700, p=101325: w ≈ 0.0106 kg/kg

Did You Know?

The constant 0.622 is the ratio of the molar masses of water and dry air.

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