Fluid Mechanics
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Torricelli's Law

Speed of fluid leaving a hole at depth h.

Formula

v=2ghv = \sqrt{2gh}

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Variables

gGravity
hDepth below surface

How it works

Torricelli’s law tells you the exit speed of a liquid jet coming out of a small hole when the fluid surface is open to the atmosphere. It comes from applying conservation of mechanical energy to a fluid parcel: the loss in gravitational potential energy from falling a vertical distance h is converted into kinetic energy, giving v = sqrt(2gh). The result assumes an ideal fluid with negligible viscosity, a small orifice, and a large tank so the surface speed is tiny compared with the outflow speed.

When to use it

Use this when you need the speed of liquid leaving a tank, reservoir, or container through a small hole at a known depth below the free surface. It is common in fluid mechanics problems involving draining tanks, jet trajectories, and idealized efflux from openings.

Worked example, step by step

A water tank has a small hole 4.5 m below the water surface. Find the speed of the water as it leaves the hole. Given: g = 9.81 m/s^2, h = 4.5 m Use Torricelli’s law: v = sqrt(2gh) Substitute the values: v = sqrt(2 × 9.81 × 4.5) Calculate inside the square root: v = sqrt(88.29) Take the square root: v ≈ 9.40 m/s Final answer: the water exits at about 9.4 m/s.

Common mistakes to avoid

  • Using the depth below the top of the tank incorrectly by measuring from the hole to the bottom instead of to the free surface
  • Forgetting that h must be in meters and g in m/s^2 so the speed comes out in m/s
  • Applying the formula to large, viscous, or pressurized flows without checking the ideal-flow assumptions

Did You Know?

Torricelli's law says fluid spurts from a hole at the same speed it would reach falling from the surface.

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Reviewed & maintained by the FormulaWon editorial teamLast reviewed September 2026