Bernoulli's Equation
Energy conservation along a streamline.
Formula
Variables
How it works
Bernoulli’s equation says that, for an ideal fluid flowing steadily along one streamline, pressure energy, kinetic energy, and gravitational potential energy can trade off without the total changing. It comes from conservation of mechanical energy applied to a tiny moving fluid element, assuming the fluid is incompressible, inviscid, and not being driven by pumps or losing energy to friction. In practice, faster flow usually means lower static pressure unless the fluid also drops in height or gains energy from outside.
When to use it
Use this for steady flow in pipes, nozzles, Venturi tubes, tank drains, and airflow over objects when the fluid can be treated as nearly incompressible and losses are small. It is especially useful for finding an unknown pressure, speed, or height difference from measurements at two points on the same streamline.
Worked example, step by step
Water flows through a horizontal pipe that narrows from point 1 to point 2. At point 1, the speed is v1 = 2.0 m/s and the pressure is P1 = 220 kPa. At point 2, the speed increases to v2 = 6.0 m/s. Find the pressure at point 2. Take water density as ρ = 1000 kg/m^3 and note that h1 = h2, so the height terms cancel. Step 1: Write Bernoulli between the two points: P1 + (1/2)ρv1^2 = P2 + (1/2)ρv2^2 Step 2: Solve for P2: P2 = P1 + (1/2)ρ(v1^2 - v2^2) Step 3: Substitute values: P2 = 220000 + (1/2)(1000)(2.0^2 - 6.0^2) P2 = 220000 + 500(4 - 36) P2 = 220000 - 16000 Step 4: Final answer: P2 = 204000 Pa = 204 kPa So the pressure drops to 204 kPa where the fluid speeds up.
Common mistakes to avoid
- Using Bernoulli across two points on different streamlines when the flow is not uniform
- Forgetting that the formula assumes the fluid is incompressible and losses from viscosity are negligible
- Mixing up pressure units or neglecting the height term when the points are at different elevations
Did You Know?
Bernoulli's principle helps explain lift: faster air over a wing's top exerts less pressure than the slower air below.
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