Bacterial Growth Count
Cell count after n binary fissions.
Formula
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Example
100 × 2^3 = 800
How it works
This formula predicts how many bacterial cells there will be after a certain number of binary fissions, assuming every cell divides successfully each generation. Because each bacterium splits into 2 cells, the population doubles every time, so after n divisions the total is the starting amount multiplied by 2^n. It is the standard model for ideal exponential growth in a well-controlled environment with enough nutrients and no death.
When to use it
Use this when you are asked to find the size of a bacterial population after a known number of divisions or generations. It is common in microbiology, lab growth calculations, and basic genetics or ecology questions involving ideal doubling.
Worked example, step by step
Start with N_0 = 50 bacteria Number of generations: n = 4 Substitute into the formula: N_t = N_0 × 2^n N_t = 50 × 2^4 N_t = 50 × 16 N_t = 800 Final answer: 800 bacteria
Common mistakes to avoid
- Using 2n instead of 2^n, which gives simple multiplication instead of doubling each generation
- Forgetting that the exponent is the number of generations, not the number of bacteria
- Starting with the final count instead of the initial count N_0
Did You Know?
Bacterial growth is exponential, which is why a tiny contamination can spoil food seemingly overnight.
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