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Logistic Growth

Population growth limited by carrying capacity.

Formula

dNdt=rN(1−NK)\frac{dN}{dt} = rN\left(1 - \frac{N}{K}\right)

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Variables

rGrowth rate
NPopulation
KCarrying capacity

How it works

This equation says a population grows fastest when it is small relative to the environment, but its growth slows as resources, space, disease, or other limits become important. The factor rN gives the familiar exponential tendency: more individuals produce more new individuals, so growth increases with population size. The term (1 - N/K) reduces that growth as N approaches the carrying capacity K, making the net growth rate fall to zero when the population is near the maximum the environment can support.

When to use it

Use this model when population increase is initially rapid but then levels off because of resource limitation, such as bacteria in a closed culture, animals in a bounded habitat, or cells in a finite growth medium. It is also useful for fitting data to estimate carrying capacity and intrinsic growth rate.

Worked example, step by step

Suppose a fish population has N = 800 individuals, growth rate r = 0.25 per year, and carrying capacity K = 2000. Step 1: Write the formula. dN/dt = rN(1 - N/K) Step 2: Substitute the values. dN/dt = 0.25(800)(1 - 800/2000) Step 3: Compute the fraction. 800/2000 = 0.4 Step 4: Compute the density-limitation term. 1 - 0.4 = 0.6 Step 5: Multiply. dN/dt = 0.25 × 800 × 0.6 = 120 Final answer: the population is increasing at 120 fish per year at that moment.

Common mistakes to avoid

  • Treating K as the current population instead of the long-term upper limit
  • Forgetting that the growth rate depends on N, so the rate changes over time
  • Assuming the population grows exponentially for all N, even when N is close to K

Did You Know?

The logistic curve bends the population explosion into an S-shape as resources run out — carrying capacity in action.

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Reviewed & maintained by the FormulaWon editorial teamLast reviewed September 2026