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United States · Grade 11 · Practice Sheet 36

Sheet code: USA-G11-S36 · 20 questions

Name: ______________
Date: ______________
  1. 1.

    A current of 2.6 A flows through a 58 Ω resistor. Find the voltage across it.

    Formula:Ohm's Law
    V=IRV = I R
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  2. 2.

    $800 is invested at 8% compound interest per annum for 4 years. Find the final amount (to 2 d.p.).

    Formula:Compound Interest
    A=P(1+r100)tA = P\left(1 + \dfrac{r}{100}\right)^{t}
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  3. 3.

    A cone has base radius 7 cm and height 6 cm. Find its volume. (π ≈ 3.14159)

    Formula:Volume of a Cone
    V=13πr2hV = \tfrac{1}{3} \pi r^2 h
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  4. 4.

    Find the volume of a sphere of radius 7 cm. (π ≈ 3.14159)

    Formula:Volume of a Sphere
    V=43πr3V = \tfrac{4}{3} \pi r^3
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  5. 5.

    Find the sum of the first 6 terms of a geometric series with first term a = 2 and common ratio r = 4.

    Formula:Sum of a Geometric Series
    Sn=a(rn1)r1S_n = \dfrac{a(r^{n} - 1)}{r - 1}
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  6. 6.

    A population of 5,500 grows 2% per year. Find its size after 3 years (nearest whole number).

    Formula:Exponential Growth
    N=N0(1+r)tN = N_0 (1 + r)^{t}
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  7. 7.

    A body starts at 2 m/s and accelerates at 3.7 m/s² for 6 s. Find its final velocity.

    Formula:Kinematics (v = u + at)
    v=u+atv = u + at
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  8. 8.

    Find the volume of a sphere of radius 7 cm. (π ≈ 3.14159)

    Formula:Volume of a Sphere
    V=43πr3V = \tfrac{4}{3} \pi r^3
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  9. 9.

    A triangle has sides a = 12 cm and b = 15 cm with an included angle C = 90°. Find its area (to 2 d.p.).

    Formula:Area of a Triangle (Sine Rule)
    A=12absinCA = \tfrac{1}{2} ab\sin C
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  10. 10.

    $500 is invested at 5% compound interest per annum for 3 years. Find the final amount (to 2 d.p.).

    Formula:Compound Interest
    A=P(1+r100)tA = P\left(1 + \dfrac{r}{100}\right)^{t}
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  11. 11.

    In a triangle, a = 13, b = 15 and the included angle C = 40°. Find side c (to 2 d.p.).

    Formula:Cosine Rule
    c=a2+b22abcosCc = \sqrt{a^2 + b^2 - 2ab\cos C}
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  12. 12.

    Find the population standard deviation of: 14, 8, 19, 14, 12 (to 2 d.p.).

    Formula:Standard Deviation (Population)
    σ=(xxˉ)2n\sigma = \sqrt{\dfrac{\sum (x - \bar{x})^2}{n}}
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  13. 13.

    A force of 41 N acts on an area of 1.7 m². Find the pressure.

    Formula:Pressure
    P=FAP = \dfrac{F}{A}
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  14. 14.

    Two masses 8,800 kg and 290 kg are 20 m apart. Find the gravitational force between them. (G = 6.674×10⁻¹¹)

    Formula:Newton’s Law of Gravitation
    F=Gm1m2r2F = G\dfrac{m_1 m_2}{r^2}
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  15. 15.

    A triangle has sides a = 7 cm and b = 11 cm with an included angle C = 60°. Find its area (to 2 d.p.).

    Formula:Area of a Triangle (Sine Rule)
    A=12absinCA = \tfrac{1}{2} ab\sin C
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  16. 16.

    A body starts at 15 m/s and accelerates at 1.6 m/s² for 4 s. Find its final velocity.

    Formula:Kinematics (v = u + at)
    v=u+atv = u + at
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  17. 17.

    Find the population standard deviation of: 16, 10, 14, 9, 19 (to 2 d.p.).

    Formula:Standard Deviation (Population)
    σ=(xxˉ)2n\sigma = \sqrt{\dfrac{\sum (x - \bar{x})^2}{n}}
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  18. 18.

    Two masses 2,600 kg and 320 kg are 10 m apart. Find the gravitational force between them. (G = 6.674×10⁻¹¹)

    Formula:Newton’s Law of Gravitation
    F=Gm1m2r2F = G\dfrac{m_1 m_2}{r^2}
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  19. 19.

    Find the gravitational potential energy of a 48 kg object raised 9 m. (g = 9.8 m/s²)

    Formula:Gravitational Potential Energy
    PE=mghPE = mgh
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  20. 20.

    Find the volume of a sphere of radius 2 cm. (π ≈ 3.14159)

    Formula:Volume of a Sphere
    V=43πr3V = \tfrac{4}{3} \pi r^3
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