View solutions
FormulaWon

Thailand · Grade 11 · Practice Sheet 37

Sheet code: THAILAND-G11-S37 · 20 questions

Name: ______________
Date: ______________
  1. 1.

    Two masses 6,900 kg and 210 kg are 10 m apart. Find the gravitational force between them. (G = 6.674×10⁻¹¹)

    Formula:Newton’s Law of Gravitation
    F=Gm1m2r2F = G\dfrac{m_1 m_2}{r^2}
    View formula →
  2. 2.

    An object with initial velocity 9 m/s accelerates at 4.7 m/s² for 5 s. Find the distance travelled.

    Formula:Kinematics (s = ut + ½at²)
    s=ut+12at2s = ut + \tfrac{1}{2}at^2
    View formula →
  3. 3.

    Find the force needed to accelerate a 19 kg mass at 3.2 m/s².

    Formula:Newton's Second Law
    F=maF = ma
    View formula →
  4. 4.

    An object has mass 133.3 g and volume 43 cm³. Find its density.

    Formula:Density
    ρ=mV\rho = \dfrac{m}{V}
    View formula →
  5. 5.

    A cone has base radius 3 cm and height 8 cm. Find its volume. (π ≈ 3.14159)

    Formula:Volume of a Cone
    V=13πr2hV = \tfrac{1}{3} \pi r^2 h
    View formula →
  6. 6.

    Two masses 1,800 kg and 310 kg are 13 m apart. Find the gravitational force between them. (G = 6.674×10⁻¹¹)

    Formula:Newton’s Law of Gravitation
    F=Gm1m2r2F = G\dfrac{m_1 m_2}{r^2}
    View formula →
  7. 7.

    A force of 350 N acts on an area of 4.4 m². Find the pressure.

    Formula:Pressure
    P=FAP = \dfrac{F}{A}
    View formula →
  8. 8.

    A cone has base radius 12 cm and height 22 cm. Find its volume. (π ≈ 3.14159)

    Formula:Volume of a Cone
    V=13πr2hV = \tfrac{1}{3} \pi r^2 h
    View formula →
  9. 9.

    A right-angled triangle has legs of 10 cm and 13 cm. Find the length of the hypotenuse.

    Formula:Pythagorean Theorem
    c=a2+b2c = \sqrt{a^2 + b^2}
    View formula →
  10. 10.

    In a triangle, a = 6, b = 17 and the included angle C = 100°. Find side c (to 2 d.p.).

    Formula:Cosine Rule
    c=a2+b22abcosCc = \sqrt{a^2 + b^2 - 2ab\cos C}
    View formula →
  11. 11.

    Two masses 1,800 kg and 810 kg are 7 m apart. Find the gravitational force between them. (G = 6.674×10⁻¹¹)

    Formula:Newton’s Law of Gravitation
    F=Gm1m2r2F = G\dfrac{m_1 m_2}{r^2}
    View formula →
  12. 12.

    A population of 4,800 grows 3% per year. Find its size after 3 years (nearest whole number).

    Formula:Exponential Growth
    N=N0(1+r)tN = N_0 (1 + r)^{t}
    View formula →
  13. 13.

    Two masses 7,700 kg and 470 kg are 16 m apart. Find the gravitational force between them. (G = 6.674×10⁻¹¹)

    Formula:Newton’s Law of Gravitation
    F=Gm1m2r2F = G\dfrac{m_1 m_2}{r^2}
    View formula →
  14. 14.

    Find the force needed to accelerate a 23 kg mass at 8.7 m/s².

    Formula:Newton's Second Law
    F=maF = ma
    View formula →
  15. 15.

    Find the gravitational potential energy of a 25 kg object raised 34 m. (g = 9.8 m/s²)

    Formula:Gravitational Potential Energy
    PE=mghPE = mgh
    View formula →
  16. 16.

    A current of 7.5 A flows through a 22 Ω resistor. Find the voltage across it.

    Formula:Ohm's Law
    V=IRV = I R
    View formula →
  17. 17.

    Find the momentum of a 55 kg object moving at 20 m/s.

    Formula:Momentum
    p=mvp = mv
    View formula →
  18. 18.

    A force of 283 N acts on an area of 8.7 m². Find the pressure.

    Formula:Pressure
    P=FAP = \dfrac{F}{A}
    View formula →
  19. 19.

    ฿1,700 is invested at 4% compound interest per annum for 5 years. Find the final amount (to 2 d.p.).

    Formula:Compound Interest
    A=P(1+r100)tA = P\left(1 + \dfrac{r}{100}\right)^{t}
    View formula →
  20. 20.

    A cylinder has radius 3 cm and height 11 cm. Find its volume. (π ≈ 3.14159)

    Formula:Volume of a Cylinder
    V=πr2hV = \pi r^2 h
    View formula →

© FormulaWon — formulawon.app · Answers & step-by-step working available on the solutions sheet.