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Sri Lanka · Grade 12 · Practice Sheet 49

Sheet code: SRI-LANKA-G12-S49 · 20 questions

Name: ______________
Date: ______________
  1. 1.

    Find the sum of the first 5 terms of an arithmetic series with first term a = 7 and common difference d = 5.

    Formula:Sum of an Arithmetic Series
    Sn=n2(2a+(n1)d)S_n = \tfrac{n}{2}\left(2a + (n-1)d\right)
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  2. 2.

    A body starts at 18 m/s and accelerates at 3.3 m/s² for 8 s. Find its final velocity.

    Formula:Kinematics (v = u + at)
    v=u+atv = u + at
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  3. 3.

    In a triangle, a = 18, b = 16 and the included angle C = 40°. Find side c (to 2 d.p.).

    Formula:Cosine Rule
    c=a2+b22abcosCc = \sqrt{a^2 + b^2 - 2ab\cos C}
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  4. 4.

    A body starts at 2 m/s and accelerates at 4.3 m/s² for 11 s. Find its final velocity.

    Formula:Kinematics (v = u + at)
    v=u+atv = u + at
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  5. 5.

    A current of 6.4 A flows through a 11 Ω resistor. Find the voltage across it.

    Formula:Ohm's Law
    V=IRV = I R
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  6. 6.

    A device runs at 131 V drawing 8.2 A. Find its power consumption.

    Formula:Electrical Power
    P=VIP = V I
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  7. 7.

    Two masses 7,700 kg and 590 kg are 2 m apart. Find the gravitational force between them. (G = 6.674×10⁻¹¹)

    Formula:Newton’s Law of Gravitation
    F=Gm1m2r2F = G\dfrac{m_1 m_2}{r^2}
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  8. 8.

    A 28 kg object moves at 14 m/s. Find its kinetic energy.

    Formula:Kinetic Energy
    KE=12mv2KE = \tfrac{1}{2} m v^2
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  9. 9.

    Find the force needed to accelerate a 46 kg mass at 5.4 m/s².

    Formula:Newton's Second Law
    F=maF = ma
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  10. 10.

    A force of 319 N acts on an area of 2.6 m². Find the pressure.

    Formula:Pressure
    P=FAP = \dfrac{F}{A}
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  11. 11.

    A force of 11 N moves an object 21 m in the direction of the force. Find the work done.

    Formula:Work Done
    W=FdW = F d
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  12. 12.

    A 35 kg object moves at 17 m/s. Find its kinetic energy.

    Formula:Kinetic Energy
    KE=12mv2KE = \tfrac{1}{2} m v^2
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  13. 13.

    Two masses 6,300 kg and 810 kg are 5 m apart. Find the gravitational force between them. (G = 6.674×10⁻¹¹)

    Formula:Newton’s Law of Gravitation
    F=Gm1m2r2F = G\dfrac{m_1 m_2}{r^2}
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  14. 14.

    Find the sum of the first 5 terms of a geometric series with first term a = 2 and common ratio r = 2.

    Formula:Sum of a Geometric Series
    Sn=a(rn1)r1S_n = \dfrac{a(r^{n} - 1)}{r - 1}
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  15. 15.

    A cone has base radius 10 cm and height 14 cm. Find its volume. (π ≈ 3.14159)

    Formula:Volume of a Cone
    V=13πr2hV = \tfrac{1}{3} \pi r^2 h
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  16. 16.

    Two masses 5,900 kg and 830 kg are 2 m apart. Find the gravitational force between them. (G = 6.674×10⁻¹¹)

    Formula:Newton’s Law of Gravitation
    F=Gm1m2r2F = G\dfrac{m_1 m_2}{r^2}
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  17. 17.

    Find the force needed to accelerate a 58 kg mass at 3.6 m/s².

    Formula:Newton's Second Law
    F=maF = ma
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  18. 18.

    A force of 77 N moves an object 14 m in the direction of the force. Find the work done.

    Formula:Work Done
    W=FdW = F d
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  19. 19.

    In a triangle, a = 11, b = 11 and the included angle C = 40°. Find side c (to 2 d.p.).

    Formula:Cosine Rule
    c=a2+b22abcosCc = \sqrt{a^2 + b^2 - 2ab\cos C}
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  20. 20.

    Find the gravitational potential energy of a 47 kg object raised 35 m. (g = 9.8 m/s²)

    Formula:Gravitational Potential Energy
    PE=mghPE = mgh
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