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Saudi Arabia · Grade 12 · Practice Sheet 50

Sheet code: SAUDI-ARABIA-G12-S50 · 20 questions

Name: ______________
Date: ______________
  1. 1.

    A 27 kg object moves at 9 m/s. Find its kinetic energy.

    Formula:Kinetic Energy
    KE=12mv2KE = \tfrac{1}{2} m v^2
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  2. 2.

    A triangle has sides a = 19 cm and b = 14 cm with an included angle C = 90°. Find its area (to 2 d.p.).

    Formula:Area of a Triangle (Sine Rule)
    A=12absinCA = \tfrac{1}{2} ab\sin C
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  3. 3.

    Solve using the quadratic formula: x² − 2x − 8 = 0.

    Formula:Quadratic Formula
    x=b±b24ac2ax = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}
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  4. 4.

    An object with initial velocity 0 m/s accelerates at 4.5 m/s² for 7 s. Find the distance travelled.

    Formula:Kinematics (s = ut + ½at²)
    s=ut+12at2s = ut + \tfrac{1}{2}at^2
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  5. 5.

    Two masses 6,600 kg and 150 kg are 9 m apart. Find the gravitational force between them. (G = 6.674×10⁻¹¹)

    Formula:Newton’s Law of Gravitation
    F=Gm1m2r2F = G\dfrac{m_1 m_2}{r^2}
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  6. 6.

    SAR 2,800 is invested at 5% compound interest per annum for 2 years. Find the final amount (to 2 d.p.).

    Formula:Compound Interest
    A=P(1+r100)tA = P\left(1 + \dfrac{r}{100}\right)^{t}
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  7. 7.

    A population of 6,800 grows 3% per year. Find its size after 6 years (nearest whole number).

    Formula:Exponential Growth
    N=N0(1+r)tN = N_0 (1 + r)^{t}
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  8. 8.

    Find the force needed to accelerate a 41 kg mass at 6.9 m/s².

    Formula:Newton's Second Law
    F=maF = ma
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  9. 9.

    Find the population standard deviation of: 10, 8, 5, 16, 15 (to 2 d.p.).

    Formula:Standard Deviation (Population)
    σ=(xxˉ)2n\sigma = \sqrt{\dfrac{\sum (x - \bar{x})^2}{n}}
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  10. 10.

    Two masses 1,400 kg and 590 kg are 18 m apart. Find the gravitational force between them. (G = 6.674×10⁻¹¹)

    Formula:Newton’s Law of Gravitation
    F=Gm1m2r2F = G\dfrac{m_1 m_2}{r^2}
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  11. 11.

    An object with initial velocity 12 m/s accelerates at 2.1 m/s² for 3 s. Find the distance travelled.

    Formula:Kinematics (s = ut + ½at²)
    s=ut+12at2s = ut + \tfrac{1}{2}at^2
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  12. 12.

    A current of 4.1 A flows through a 11 Ω resistor. Find the voltage across it.

    Formula:Ohm's Law
    V=IRV = I R
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  13. 13.

    A body starts at 4 m/s and accelerates at 5.2 m/s² for 7 s. Find its final velocity.

    Formula:Kinematics (v = u + at)
    v=u+atv = u + at
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  14. 14.

    Solve using the quadratic formula: x² + 7x + 12 = 0.

    Formula:Quadratic Formula
    x=b±b24ac2ax = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}
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  15. 15.

    Find the force needed to accelerate a 37 kg mass at 6.1 m/s².

    Formula:Newton's Second Law
    F=maF = ma
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  16. 16.

    SAR 1,100 is invested at 4% compound interest per annum for 3 years. Find the final amount (to 2 d.p.).

    Formula:Compound Interest
    A=P(1+r100)tA = P\left(1 + \dfrac{r}{100}\right)^{t}
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  17. 17.

    Solve using the quadratic formula: x² + 2x − 8 = 0.

    Formula:Quadratic Formula
    x=b±b24ac2ax = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}
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  18. 18.

    A device runs at 42 V drawing 5.1 A. Find its power consumption.

    Formula:Electrical Power
    P=VIP = V I
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  19. 19.

    Find the force needed to accelerate a 53 kg mass at 3.2 m/s².

    Formula:Newton's Second Law
    F=maF = ma
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  20. 20.

    SAR 1,500 is invested at 8% compound interest per annum for 2 years. Find the final amount (to 2 d.p.).

    Formula:Compound Interest
    A=P(1+r100)tA = P\left(1 + \dfrac{r}{100}\right)^{t}
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