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Russia · Grade 12 · Practice Sheet 23

Sheet code: RUSSIA-G12-S23 · 20 questions

Name: ______________
Date: ______________
  1. 1.

    A current of 3.3 A flows through a 32 Ω resistor. Find the voltage across it.

    Formula:Ohm's Law
    V=IRV = I R
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  2. 2.

    A 18 kg object moves at 7 m/s. Find its kinetic energy.

    Formula:Kinetic Energy
    KE=12mv2KE = \tfrac{1}{2} m v^2
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  3. 3.

    Two masses 3,400 kg and 830 kg are 10 m apart. Find the gravitational force between them. (G = 6.674×10⁻¹¹)

    Formula:Newton’s Law of Gravitation
    F=Gm1m2r2F = G\dfrac{m_1 m_2}{r^2}
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  4. 4.

    Solve using the quadratic formula: x² − 7x + 12 = 0.

    Formula:Quadratic Formula
    x=b±b24ac2ax = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}
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  5. 5.

    Two masses 8,800 kg and 260 kg are 17 m apart. Find the gravitational force between them. (G = 6.674×10⁻¹¹)

    Formula:Newton’s Law of Gravitation
    F=Gm1m2r2F = G\dfrac{m_1 m_2}{r^2}
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  6. 6.

    Find the population standard deviation of: 3, 7, 3, 5, 2 (to 2 d.p.).

    Formula:Standard Deviation (Population)
    σ=(xxˉ)2n\sigma = \sqrt{\dfrac{\sum (x - \bar{x})^2}{n}}
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  7. 7.

    A body starts at 10 m/s and accelerates at 1.3 m/s² for 5 s. Find its final velocity.

    Formula:Kinematics (v = u + at)
    v=u+atv = u + at
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  8. 8.

    Find the volume of a sphere of radius 7 cm. (π ≈ 3.14159)

    Formula:Volume of a Sphere
    V=43πr3V = \tfrac{4}{3} \pi r^3
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  9. 9.

    Solve using the quadratic formula: x² + 5x + 6 = 0.

    Formula:Quadratic Formula
    x=b±b24ac2ax = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}
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  10. 10.

    A body starts at 12 m/s and accelerates at 3.7 m/s² for 11 s. Find its final velocity.

    Formula:Kinematics (v = u + at)
    v=u+atv = u + at
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  11. 11.

    In a triangle, a = 17, b = 11 and the included angle C = 70°. Find side c (to 2 d.p.).

    Formula:Cosine Rule
    c=a2+b22abcosCc = \sqrt{a^2 + b^2 - 2ab\cos C}
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  12. 12.

    ₽3,800 is invested at 6% compound interest per annum for 5 years. Find the final amount (to 2 d.p.).

    Formula:Compound Interest
    A=P(1+r100)tA = P\left(1 + \dfrac{r}{100}\right)^{t}
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  13. 13.

    Two masses 4,400 kg and 250 kg are 3 m apart. Find the gravitational force between them. (G = 6.674×10⁻¹¹)

    Formula:Newton’s Law of Gravitation
    F=Gm1m2r2F = G\dfrac{m_1 m_2}{r^2}
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  14. 14.

    A triangle has sides a = 11 cm and b = 12 cm with an included angle C = 45°. Find its area (to 2 d.p.).

    Formula:Area of a Triangle (Sine Rule)
    A=12absinCA = \tfrac{1}{2} ab\sin C
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  15. 15.

    Find the population standard deviation of: 14, 13, 12, 6, 10 (to 2 d.p.).

    Formula:Standard Deviation (Population)
    σ=(xxˉ)2n\sigma = \sqrt{\dfrac{\sum (x - \bar{x})^2}{n}}
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  16. 16.

    A cone has base radius 11 cm and height 14 cm. Find its volume. (π ≈ 3.14159)

    Formula:Volume of a Cone
    V=13πr2hV = \tfrac{1}{3} \pi r^2 h
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  17. 17.

    In a triangle, a = 13, b = 12 and the included angle C = 110°. Find side c (to 2 d.p.).

    Formula:Cosine Rule
    c=a2+b22abcosCc = \sqrt{a^2 + b^2 - 2ab\cos C}
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  18. 18.

    ₽1,600 is invested at 8% compound interest per annum for 4 years. Find the final amount (to 2 d.p.).

    Formula:Compound Interest
    A=P(1+r100)tA = P\left(1 + \dfrac{r}{100}\right)^{t}
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  19. 19.

    A current of 0.8 A flows through a 30 Ω resistor. Find the voltage across it.

    Formula:Ohm's Law
    V=IRV = I R
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  20. 20.

    Two masses 2,200 kg and 340 kg are 2 m apart. Find the gravitational force between them. (G = 6.674×10⁻¹¹)

    Formula:Newton’s Law of Gravitation
    F=Gm1m2r2F = G\dfrac{m_1 m_2}{r^2}
    View formula →

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