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Nepal · Class 12 · Practice Sheet 17

Sheet code: NEPAL-G12-S17 · 20 questions

Name: ______________
Date: ______________
  1. 1.

    Find the volume of a sphere of radius 8 cm. (π ≈ 3.14159)

    Formula:Volume of a Sphere
    V=43πr3V = \tfrac{4}{3} \pi r^3
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  2. 2.

    Solve using the quadratic formula: x² + 3x − 10 = 0.

    Formula:Quadratic Formula
    x=b±b24ac2ax = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}
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  3. 3.

    Find the gravitational potential energy of a 31 kg object raised 15 m. (g = 9.8 m/s²)

    Formula:Gravitational Potential Energy
    PE=mghPE = mgh
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  4. 4.

    Find the population standard deviation of: 8, 16, 4, 10, 12 (to 2 d.p.).

    Formula:Standard Deviation (Population)
    σ=(xxˉ)2n\sigma = \sqrt{\dfrac{\sum (x - \bar{x})^2}{n}}
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  5. 5.

    Find the gravitational potential energy of a 23 kg object raised 25 m. (g = 9.8 m/s²)

    Formula:Gravitational Potential Energy
    PE=mghPE = mgh
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  6. 6.

    Find the population standard deviation of: 14, 20, 10, 11, 12 (to 2 d.p.).

    Formula:Standard Deviation (Population)
    σ=(xxˉ)2n\sigma = \sqrt{\dfrac{\sum (x - \bar{x})^2}{n}}
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  7. 7.

    Find the momentum of a 28 kg object moving at 20 m/s.

    Formula:Momentum
    p=mvp = mv
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  8. 8.

    Solve using the quadratic formula: x² − 1x − 2 = 0.

    Formula:Quadratic Formula
    x=b±b24ac2ax = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}
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  9. 9.

    Two masses 3,500 kg and 580 kg are 15 m apart. Find the gravitational force between them. (G = 6.674×10⁻¹¹)

    Formula:Newton’s Law of Gravitation
    F=Gm1m2r2F = G\dfrac{m_1 m_2}{r^2}
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  10. 10.

    Find the sum of the first 6 terms of a geometric series with first term a = 1 and common ratio r = 4.

    Formula:Sum of a Geometric Series
    Sn=a(rn1)r1S_n = \dfrac{a(r^{n} - 1)}{r - 1}
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  11. 11.

    Solve using the quadratic formula: x² − 9x + 18 = 0.

    Formula:Quadratic Formula
    x=b±b24ac2ax = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}
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  12. 12.

    A triangle has sides a = 5 cm and b = 8 cm with an included angle C = 120°. Find its area (to 2 d.p.).

    Formula:Area of a Triangle (Sine Rule)
    A=12absinCA = \tfrac{1}{2} ab\sin C
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  13. 13.

    Find the gravitational potential energy of a 10 kg object raised 9 m. (g = 9.8 m/s²)

    Formula:Gravitational Potential Energy
    PE=mghPE = mgh
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  14. 14.

    A population of 7,700 grows 3% per year. Find its size after 8 years (nearest whole number).

    Formula:Exponential Growth
    N=N0(1+r)tN = N_0 (1 + r)^{t}
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  15. 15.

    A current of 3.2 A flows through a 40 Ω resistor. Find the voltage across it.

    Formula:Ohm's Law
    V=IRV = I R
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  16. 16.

    Solve using the quadratic formula: x² + 1x − 2 = 0.

    Formula:Quadratic Formula
    x=b±b24ac2ax = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}
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  17. 17.

    An object with initial velocity 11 m/s accelerates at 2.3 m/s² for 2 s. Find the distance travelled.

    Formula:Kinematics (s = ut + ½at²)
    s=ut+12at2s = ut + \tfrac{1}{2}at^2
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  18. 18.

    Find the force needed to accelerate a 26 kg mass at 6.9 m/s².

    Formula:Newton's Second Law
    F=maF = ma
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  19. 19.

    In a triangle, a = 15, b = 12 and the included angle C = 60°. Find side c (to 2 d.p.).

    Formula:Cosine Rule
    c=a2+b22abcosCc = \sqrt{a^2 + b^2 - 2ab\cos C}
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  20. 20.

    Rs 1,700 is invested at 3% compound interest per annum for 4 years. Find the final amount (to 2 d.p.).

    Formula:Compound Interest
    A=P(1+r100)tA = P\left(1 + \dfrac{r}{100}\right)^{t}
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