View solutions
FormulaWon

Jordan · Grade 11 · Practice Sheet 28

Sheet code: JORDAN-G11-S28 · 20 questions

Name: ______________
Date: ______________
  1. 1.

    A cylinder has radius 10 cm and height 6 cm. Find its volume. (π ≈ 3.14159)

    Formula:Volume of a Cylinder
    V=πr2hV = \pi r^2 h
    View formula →
  2. 2.

    A current of 4.9 A flows through a 24 Ω resistor. Find the voltage across it.

    Formula:Ohm's Law
    V=IRV = I R
    View formula →
  3. 3.

    Solve using the quadratic formula: x² − 2x − 8 = 0.

    Formula:Quadratic Formula
    x=b±b24ac2ax = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}
    View formula →
  4. 4.

    A right-angled triangle has legs of 19 cm and 14 cm. Find the length of the hypotenuse.

    Formula:Pythagorean Theorem
    c=a2+b2c = \sqrt{a^2 + b^2}
    View formula →
  5. 5.

    JD 2,700 is invested at 5% compound interest per annum for 5 years. Find the final amount (to 2 d.p.).

    Formula:Compound Interest
    A=P(1+r100)tA = P\left(1 + \dfrac{r}{100}\right)^{t}
    View formula →
  6. 6.

    Find the momentum of a 2 kg object moving at 19 m/s.

    Formula:Momentum
    p=mvp = mv
    View formula →
  7. 7.

    A cone has base radius 3 cm and height 7 cm. Find its volume. (π ≈ 3.14159)

    Formula:Volume of a Cone
    V=13πr2hV = \tfrac{1}{3} \pi r^2 h
    View formula →
  8. 8.

    A cylinder has radius 11 cm and height 30 cm. Find its volume. (π ≈ 3.14159)

    Formula:Volume of a Cylinder
    V=πr2hV = \pi r^2 h
    View formula →
  9. 9.

    A cone has base radius 2 cm and height 19 cm. Find its volume. (π ≈ 3.14159)

    Formula:Volume of a Cone
    V=13πr2hV = \tfrac{1}{3} \pi r^2 h
    View formula →
  10. 10.

    Find the momentum of a 43 kg object moving at 14 m/s.

    Formula:Momentum
    p=mvp = mv
    View formula →
  11. 11.

    Find the population standard deviation of: 7, 18, 10, 5, 8 (to 2 d.p.).

    Formula:Standard Deviation (Population)
    σ=(xxˉ)2n\sigma = \sqrt{\dfrac{\sum (x - \bar{x})^2}{n}}
    View formula →
  12. 12.

    An object with initial velocity 2 m/s accelerates at 3.3 m/s² for 4 s. Find the distance travelled.

    Formula:Kinematics (s = ut + ½at²)
    s=ut+12at2s = ut + \tfrac{1}{2}at^2
    View formula →
  13. 13.

    Find the force needed to accelerate a 59 kg mass at 8.2 m/s².

    Formula:Newton's Second Law
    F=maF = ma
    View formula →
  14. 14.

    A current of 6.7 A flows through a 18 Ω resistor. Find the voltage across it.

    Formula:Ohm's Law
    V=IRV = I R
    View formula →
  15. 15.

    An object with initial velocity 14 m/s accelerates at 2.3 m/s² for 9 s. Find the distance travelled.

    Formula:Kinematics (s = ut + ½at²)
    s=ut+12at2s = ut + \tfrac{1}{2}at^2
    View formula →
  16. 16.

    A current of 5 A flows through a 17 Ω resistor. Find the voltage across it.

    Formula:Ohm's Law
    V=IRV = I R
    View formula →
  17. 17.

    In a triangle, a = 9, b = 13 and the included angle C = 100°. Find side c (to 2 d.p.).

    Formula:Cosine Rule
    c=a2+b22abcosCc = \sqrt{a^2 + b^2 - 2ab\cos C}
    View formula →
  18. 18.

    Two masses 3,700 kg and 550 kg are 4 m apart. Find the gravitational force between them. (G = 6.674×10⁻¹¹)

    Formula:Newton’s Law of Gravitation
    F=Gm1m2r2F = G\dfrac{m_1 m_2}{r^2}
    View formula →
  19. 19.

    A device runs at 68 V drawing 1.6 A. Find its power consumption.

    Formula:Electrical Power
    P=VIP = V I
    View formula →
  20. 20.

    A body starts at 18 m/s and accelerates at 3 m/s² for 6 s. Find its final velocity.

    Formula:Kinematics (v = u + at)
    v=u+atv = u + at
    View formula →

© FormulaWon — formulawon.app · Answers & step-by-step working available on the solutions sheet.