View solutions
FormulaWon

Engineering Entrance · Practice Sheet 35

Sheet code: UAE-ENGINEERING-S35 · 20 questions

Name: ______________
Date: ______________
  1. 1.
    Chemistry

    Find the pH of a solution with [H⁺] = 1×10⁻2 mol/L.

    Formula:pH of a Solution
    pH=log10[H+]pH = -\log_{10}[H^{+}]
    View formula →
  2. 2.
    Mathematics

    Find the slope of the line through (7, -2) and (-4, 8).

    Formula:Slope of a Line
    m=y2y1x2x1m = \dfrac{y_2-y_1}{x_2-x_1}
    View formula →
  3. 3.
    Chemistry

    Find the molarity of a solution containing 1 mol of solute in 1 L of solution.

    Formula:Molarity
    M=nVM = \dfrac{n}{V}
    View formula →
  4. 4.
    Chemistry

    Find the pressure of 2 mol of an ideal gas at 337 K in a 14 L container (R = 0.0821 L·atm·mol⁻¹·K⁻¹).

    Formula:Ideal Gas Law
    PV=nRTPV = nRT
    View formula →
  5. 5.
    Chemistry

    Find the pH of a solution with [H⁺] = 1×10⁻2 mol/L.

    Formula:pH of a Solution
    pH=log10[H+]pH = -\log_{10}[H^{+}]
    View formula →
  6. 6.
    Physics

    Find the force required to accelerate a 13 kg mass at 5 m/s².

    Formula:Newton's Second Law (F = ma)
    F=maF = ma
    View formula →
  7. 7.
    Mathematics

    Evaluate log base 3 of 27.

    Formula:Logarithm Evaluation
    logb(bk)=k\log_{b}(b^{k}) = k
    View formula →
  8. 8.
    Physics

    Find the voltage across a 38 Ω resistor carrying a current of 18 A.

    Formula:Ohm's Law
    V=IRV = IR
    View formula →
  9. 9.
    Physics

    Find the electrical power when 181 V drives a current of 4 A.

    Formula:Electrical Power
    P=VIP = VI
    View formula →
  10. 10.
    Mathematics

    Find the binomial coefficient C(5, 3) — the coefficient of x^3 in (1 + x)^5.

    Formula:Binomial Coefficient
    (nr)=n!r!(nr)!\binom{n}{r} = \dfrac{n!}{r!\,(n-r)!}
    View formula →
  11. 11.
    Physics

    An object starts at 12 m/s and accelerates at 6 m/s² for 3 s. Find its final velocity.

    Formula:Equation of Motion (v = u + at)
    v=u+atv = u + at
    View formula →
  12. 12.
    Chemistry

    41 mL of a 10 M solution is diluted to 350 mL. Find the new concentration.

    Formula:Dilution
    M1V1=M2V2M_1V_1 = M_2V_2
    View formula →
  13. 13.
    Physics

    A body moving at 8 m/s accelerates at 1 m/s² for 6 s. Find the distance travelled.

    Formula:Equation of Motion (s = ut + ½at²)
    s=ut+12at2s = ut + \tfrac{1}{2}at^{2}
    View formula →
  14. 14.
    Physics

    Find the voltage across a 41 Ω resistor carrying a current of 14 A.

    Formula:Ohm's Law
    V=IRV = IR
    View formula →
  15. 15.
    Physics

    Find the kinetic energy of a 4 kg object moving at 26 m/s.

    Formula:Kinetic Energy
    KE=12mv2KE = \tfrac{1}{2}mv^{2}
    View formula →
  16. 16.
    Mathematics

    Evaluate ∫ from 1 to 4 of 4x^1 dx.

    Formula:Definite Integral of a Power
    pqaxndx=an+1[xn+1]pq\int_{p}^{q} a x^{n}\,dx = \dfrac{a}{n+1}\big[x^{n+1}\big]_{p}^{q}
    View formula →
  17. 17.
    Physics

    An object starts at 17 m/s and accelerates at 7 m/s² for 12 s. Find its final velocity.

    Formula:Equation of Motion (v = u + at)
    v=u+atv = u + at
    View formula →
  18. 18.
    Physics

    A body moving at 9 m/s accelerates at 1 m/s² for 9 s. Find the distance travelled.

    Formula:Equation of Motion (s = ut + ½at²)
    s=ut+12at2s = ut + \tfrac{1}{2}at^{2}
    View formula →
  19. 19.
    Chemistry

    44 mL of a 1 M solution is diluted to 255 mL. Find the new concentration.

    Formula:Dilution
    M1V1=M2V2M_1V_1 = M_2V_2
    View formula →
  20. 20.
    Physics

    Find the force required to accelerate a 23 kg mass at 11 m/s².

    Formula:Newton's Second Law (F = ma)
    F=maF = ma
    View formula →

© FormulaWon — formulawon.app · Answers & step-by-step working available on the solutions sheet.