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Chile · Grado 12 · Practice Sheet 5

Sheet code: CHILE-G12-S05 · 20 questions

Name: ______________
Date: ______________
  1. 1.

    Find the force needed to accelerate a 54 kg mass at 2 m/s².

    Formula:Newton's Second Law
    F=maF = ma
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  2. 2.

    Find the population standard deviation of: 13, 20, 5, 5, 9 (to 2 d.p.).

    Formula:Standard Deviation (Population)
    σ=(xxˉ)2n\sigma = \sqrt{\dfrac{\sum (x - \bar{x})^2}{n}}
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  3. 3.

    Solve using the quadratic formula: x² + 10x + 24 = 0.

    Formula:Quadratic Formula
    x=b±b24ac2ax = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}
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  4. 4.

    A population of 3,100 grows 3% per year. Find its size after 7 years (nearest whole number).

    Formula:Exponential Growth
    N=N0(1+r)tN = N_0 (1 + r)^{t}
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  5. 5.

    A cone has base radius 10 cm and height 23 cm. Find its volume. (π ≈ 3.14159)

    Formula:Volume of a Cone
    V=13πr2hV = \tfrac{1}{3} \pi r^2 h
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  6. 6.

    $1,400 is invested at 8% compound interest per annum for 2 years. Find the final amount (to 2 d.p.).

    Formula:Compound Interest
    A=P(1+r100)tA = P\left(1 + \dfrac{r}{100}\right)^{t}
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  7. 7.

    A current of 0.8 A flows through a 6 Ω resistor. Find the voltage across it.

    Formula:Ohm's Law
    V=IRV = I R
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  8. 8.

    An object with initial velocity 1 m/s accelerates at 2.2 m/s² for 8 s. Find the distance travelled.

    Formula:Kinematics (s = ut + ½at²)
    s=ut+12at2s = ut + \tfrac{1}{2}at^2
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  9. 9.

    A current of 3 A flows through a 54 Ω resistor. Find the voltage across it.

    Formula:Ohm's Law
    V=IRV = I R
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  10. 10.

    Find the population standard deviation of: 10, 19, 12, 13, 13 (to 2 d.p.).

    Formula:Standard Deviation (Population)
    σ=(xxˉ)2n\sigma = \sqrt{\dfrac{\sum (x - \bar{x})^2}{n}}
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  11. 11.

    A force of 343 N acts on an area of 7.4 m². Find the pressure.

    Formula:Pressure
    P=FAP = \dfrac{F}{A}
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  12. 12.

    A current of 5.5 A flows through a 57 Ω resistor. Find the voltage across it.

    Formula:Ohm's Law
    V=IRV = I R
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  13. 13.

    Solve using the quadratic formula: x² + 3x + 0 = 0.

    Formula:Quadratic Formula
    x=b±b24ac2ax = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}
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  14. 14.

    Find the volume of a sphere of radius 8 cm. (π ≈ 3.14159)

    Formula:Volume of a Sphere
    V=43πr3V = \tfrac{4}{3} \pi r^3
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  15. 15.

    A population of 2,500 grows 2% per year. Find its size after 7 years (nearest whole number).

    Formula:Exponential Growth
    N=N0(1+r)tN = N_0 (1 + r)^{t}
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  16. 16.

    Find the volume of a sphere of radius 8 cm. (π ≈ 3.14159)

    Formula:Volume of a Sphere
    V=43πr3V = \tfrac{4}{3} \pi r^3
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  17. 17.

    A population of 5,400 grows 5% per year. Find its size after 8 years (nearest whole number).

    Formula:Exponential Growth
    N=N0(1+r)tN = N_0 (1 + r)^{t}
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  18. 18.

    A force of 103 N moves an object 14 m in the direction of the force. Find the work done.

    Formula:Work Done
    W=FdW = F d
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  19. 19.

    Two masses 4,700 kg and 610 kg are 6 m apart. Find the gravitational force between them. (G = 6.674×10⁻¹¹)

    Formula:Newton’s Law of Gravitation
    F=Gm1m2r2F = G\dfrac{m_1 m_2}{r^2}
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  20. 20.

    Find the gravitational potential energy of a 49 kg object raised 38 m. (g = 9.8 m/s²)

    Formula:Gravitational Potential Energy
    PE=mghPE = mgh
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