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Chile · Grado 12 · Practice Sheet 48

Sheet code: CHILE-G12-S48 · 20 questions

Name: ______________
Date: ______________
  1. 1.

    Two masses 4,100 kg and 560 kg are 15 m apart. Find the gravitational force between them. (G = 6.674×10⁻¹¹)

    Formula:Newton’s Law of Gravitation
    F=Gm1m2r2F = G\dfrac{m_1 m_2}{r^2}
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  2. 2.

    A current of 3.3 A flows through a 54 Ω resistor. Find the voltage across it.

    Formula:Ohm's Law
    V=IRV = I R
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  3. 3.

    A 11 kg object moves at 23 m/s. Find its kinetic energy.

    Formula:Kinetic Energy
    KE=12mv2KE = \tfrac{1}{2} m v^2
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  4. 4.

    A triangle has sides a = 9 cm and b = 12 cm with an included angle C = 120°. Find its area (to 2 d.p.).

    Formula:Area of a Triangle (Sine Rule)
    A=12absinCA = \tfrac{1}{2} ab\sin C
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  5. 5.

    Find the momentum of a 5 kg object moving at 3 m/s.

    Formula:Momentum
    p=mvp = mv
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  6. 6.

    Find the sum of the first 7 terms of a geometric series with first term a = 8 and common ratio r = 2.

    Formula:Sum of a Geometric Series
    Sn=a(rn1)r1S_n = \dfrac{a(r^{n} - 1)}{r - 1}
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  7. 7.

    Find the momentum of a 41 kg object moving at 23 m/s.

    Formula:Momentum
    p=mvp = mv
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  8. 8.

    A force of 246 N acts on an area of 5.3 m². Find the pressure.

    Formula:Pressure
    P=FAP = \dfrac{F}{A}
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  9. 9.

    $2,500 is invested at 6% compound interest per annum for 2 years. Find the final amount (to 2 d.p.).

    Formula:Compound Interest
    A=P(1+r100)tA = P\left(1 + \dfrac{r}{100}\right)^{t}
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  10. 10.

    Find the gravitational potential energy of a 8 kg object raised 19 m. (g = 9.8 m/s²)

    Formula:Gravitational Potential Energy
    PE=mghPE = mgh
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  11. 11.

    Solve using the quadratic formula: x² + 8x + 15 = 0.

    Formula:Quadratic Formula
    x=b±b24ac2ax = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}
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  12. 12.

    Two masses 7,600 kg and 380 kg are 20 m apart. Find the gravitational force between them. (G = 6.674×10⁻¹¹)

    Formula:Newton’s Law of Gravitation
    F=Gm1m2r2F = G\dfrac{m_1 m_2}{r^2}
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  13. 13.

    In a triangle, a = 14, b = 12 and the included angle C = 100°. Find side c (to 2 d.p.).

    Formula:Cosine Rule
    c=a2+b22abcosCc = \sqrt{a^2 + b^2 - 2ab\cos C}
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  14. 14.

    Two masses 2,400 kg and 130 kg are 18 m apart. Find the gravitational force between them. (G = 6.674×10⁻¹¹)

    Formula:Newton’s Law of Gravitation
    F=Gm1m2r2F = G\dfrac{m_1 m_2}{r^2}
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  15. 15.

    Find the momentum of a 53 kg object moving at 21 m/s.

    Formula:Momentum
    p=mvp = mv
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  16. 16.

    A current of 2.9 A flows through a 56 Ω resistor. Find the voltage across it.

    Formula:Ohm's Law
    V=IRV = I R
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  17. 17.

    Two masses 5,200 kg and 620 kg are 5 m apart. Find the gravitational force between them. (G = 6.674×10⁻¹¹)

    Formula:Newton’s Law of Gravitation
    F=Gm1m2r2F = G\dfrac{m_1 m_2}{r^2}
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  18. 18.

    Find the gravitational potential energy of a 34 kg object raised 5 m. (g = 9.8 m/s²)

    Formula:Gravitational Potential Energy
    PE=mghPE = mgh
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  19. 19.

    Find the force needed to accelerate a 16 kg mass at 2.8 m/s².

    Formula:Newton's Second Law
    F=maF = ma
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  20. 20.

    A triangle has sides a = 19 cm and b = 20 cm with an included angle C = 60°. Find its area (to 2 d.p.).

    Formula:Area of a Triangle (Sine Rule)
    A=12absinCA = \tfrac{1}{2} ab\sin C
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