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Chile · Grado 10 · Practice Sheet 28

Sheet code: CHILE-G10-S28 · 20 questions

Name: ______________
Date: ______________
  1. 1.

    A triangle has sides a = 17 cm and b = 12 cm with an included angle C = 90°. Find its area (to 2 d.p.).

    Formula:Area of a Triangle (Sine Rule)
    A=12absinCA = \tfrac{1}{2} ab\sin C
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  2. 2.

    A force of 109 N moves an object 23 m in the direction of the force. Find the work done.

    Formula:Work Done
    W=FdW = F d
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  3. 3.

    Find the sum of the first 12 terms of an arithmetic series with first term a = 6 and common difference d = 6.

    Formula:Sum of an Arithmetic Series
    Sn=n2(2a+(n1)d)S_n = \tfrac{n}{2}\left(2a + (n-1)d\right)
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  4. 4.

    An object has mass 86.4 g and volume 48 cm³. Find its density.

    Formula:Density
    ρ=mV\rho = \dfrac{m}{V}
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  5. 5.

    A cone has base radius 6 cm and height 17 cm. Find its volume. (π ≈ 3.14159)

    Formula:Volume of a Cone
    V=13πr2hV = \tfrac{1}{3} \pi r^2 h
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  6. 6.

    $2,400 is invested at 5% compound interest per annum for 4 years. Find the final amount (to 2 d.p.).

    Formula:Compound Interest
    A=P(1+r100)tA = P\left(1 + \dfrac{r}{100}\right)^{t}
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  7. 7.

    Find the momentum of a 47 kg object moving at 28 m/s.

    Formula:Momentum
    p=mvp = mv
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  8. 8.

    $3,000 is invested at 3% compound interest per annum for 4 years. Find the final amount (to 2 d.p.).

    Formula:Compound Interest
    A=P(1+r100)tA = P\left(1 + \dfrac{r}{100}\right)^{t}
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  9. 9.

    A triangle has sides a = 15 cm and b = 8 cm with an included angle C = 60°. Find its area (to 2 d.p.).

    Formula:Area of a Triangle (Sine Rule)
    A=12absinCA = \tfrac{1}{2} ab\sin C
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  10. 10.

    Find the sum of the first 6 terms of an arithmetic series with first term a = 8 and common difference d = 5.

    Formula:Sum of an Arithmetic Series
    Sn=n2(2a+(n1)d)S_n = \tfrac{n}{2}\left(2a + (n-1)d\right)
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  11. 11.

    An object with initial velocity 1 m/s accelerates at 3.3 m/s² for 9 s. Find the distance travelled.

    Formula:Kinematics (s = ut + ½at²)
    s=ut+12at2s = ut + \tfrac{1}{2}at^2
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  12. 12.

    Solve for x: 6x + 20 = 62.

    Formula:Solving a Linear Equation
    x=cbax = \dfrac{c - b}{a}
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  13. 13.

    A value changes from 181 to 51. Find the percentage change (to 2 d.p.).

    Formula:Percentage Change
    %change=newoldold×100\%\,\text{change} = \dfrac{\text{new} - \text{old}}{\text{old}} \times 100
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  14. 14.

    Find the momentum of a 53 kg object moving at 25 m/s.

    Formula:Momentum
    p=mvp = mv
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  15. 15.

    An object with initial velocity 15 m/s accelerates at 1.3 m/s² for 7 s. Find the distance travelled.

    Formula:Kinematics (s = ut + ½at²)
    s=ut+12at2s = ut + \tfrac{1}{2}at^2
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  16. 16.

    A force of 114 N moves an object 34 m in the direction of the force. Find the work done.

    Formula:Work Done
    W=FdW = F d
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  17. 17.

    Find the sum of the first 14 terms of an arithmetic series with first term a = 9 and common difference d = 5.

    Formula:Sum of an Arithmetic Series
    Sn=n2(2a+(n1)d)S_n = \tfrac{n}{2}\left(2a + (n-1)d\right)
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  18. 18.

    A value changes from 92 to 60. Find the percentage change (to 2 d.p.).

    Formula:Percentage Change
    %change=newoldold×100\%\,\text{change} = \dfrac{\text{new} - \text{old}}{\text{old}} \times 100
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  19. 19.

    A cone has base radius 4 cm and height 22 cm. Find its volume. (π ≈ 3.14159)

    Formula:Volume of a Cone
    V=13πr2hV = \tfrac{1}{3} \pi r^2 h
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  20. 20.

    Find the force needed to accelerate a 52 kg mass at 8.8 m/s².

    Formula:Newton's Second Law
    F=maF = ma
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