Trigonometry
Basic

Pythagorean Identity

The fundamental trig identity from the unit circle.

Formula

sin⁡2θ+cos⁡2θ=1\sin^2\theta + \cos^2\theta = 1

Variables

\thetaAngle

Example

If sinθ=0.6, cosθ=0.8

How it works

For any angle \(\theta\), the point on the unit circle has coordinates \((\cos\theta, \sin\theta)\). Since every point on the unit circle is exactly 1 unit from the origin, the coordinates must satisfy the distance formula \(x^2+y^2=1\), which becomes \(\cos^2\theta+\sin^2\theta=1\). This identity is true for every angle, not just special angles, and it links the horizontal and vertical parts of the same unit-circle point.

When to use it

Use this identity when you know one trig function and need the other, especially in algebraic simplification or solving trig equations. It is also helpful for checking whether trig values are reasonable and for converting between sine and cosine in unit-circle problems.

Worked example, step by step

Given \(\cos\theta=\frac{5}{13}\), find \(\sin\theta\) if \(\theta\) is in Quadrant I. Start with the identity: \(\sin^2\theta+\cos^2\theta=1\) Substitute \(\cos\theta=\frac{5}{13}\): \(\sin^2\theta+\left(\frac{5}{13}\right)^2=1\) Square the fraction: \(\sin^2\theta+\frac{25}{169}=1\) Subtract \(\frac{25}{169}\) from both sides: \(\sin^2\theta=\frac{144}{169}\) Take the square root: \(\sin\theta=\pm\frac{12}{13}\) Because \(\theta\) is in Quadrant I, sine is positive. Final answer: \(\sin\theta=\frac{12}{13}\)

Common mistakes to avoid

  • Forgetting that the identity uses squares, so writing \(\sin\theta+\cos\theta=1\)
  • Choosing the wrong sign when taking the square root after solving for \(\sin^2\theta\) or \(\cos^2\theta\)
  • Using the identity without checking the quadrant, which is needed to decide whether the final sine or cosine value is positive or negative

Did You Know?

sin²θ + cos²θ = 1 is literally the Pythagorean theorem applied to the unit circle.

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Reviewed & maintained by the FormulaWon editorial teamLast reviewed September 2026