Trigonometry
Intermediate

Identity: 1 + tan² = sec²

Derived Pythagorean identity dividing by cos².

Formula

1+tan⁡2θ=sec⁡2θ1 + \tan^2\theta = \sec^2\theta

Variables

\thetaAngle

How it works

This identity links two trig ratios for the same angle: the tangent and the secant. It comes from the Pythagorean identity \(\sin^2\theta + \cos^2\theta = 1\); if you divide every term by \(\cos^2\theta\), you get \(\tan^2\theta + 1 = \sec^2\theta\). The formula is true for every angle where \(\cos\theta \neq 0\), since both \(\tan\theta\) and \(\sec\theta\) must be defined.

When to use it

Use this identity when you need to simplify trig expressions, prove another identity, or rewrite everything in terms of tangent or secant. It is also useful in calculus and physics when expressions contain \(\tan\theta\) and \(\sec\theta\) together.

Worked example, step by step

Find \(\sec\theta\) if \(\tan\theta = 3\) and \(\theta\) is an angle where the identity applies. Start with \(1 + \tan^2\theta = \sec^2\theta\). Substitute \(\tan\theta = 3\): \(1 + 3^2 = \sec^2\theta\). Calculate: \(1 + 9 = \sec^2\theta\). So \(\sec^2\theta = 10\). Take the square root: \(\sec\theta = \pm\sqrt{10}\). If the quadrant or context shows \(\sec\theta\) is positive, then \(\sec\theta = \sqrt{10}\).

Common mistakes to avoid

  • Forgetting that the identity is \(1 + \tan^2\theta = \sec^2\theta\), not \(1 + \tan\theta = \sec\theta\)
  • Using the identity when \(\cos\theta = 0\), where tangent and secant are undefined
  • Taking \(\sec\theta = \sqrt{1+\tan^2\theta}\) without considering that square roots can be positive or negative depending on the situation

Did You Know?

This identity is just the Pythagorean theorem in disguise, divided through by cos².

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Reviewed & maintained by the FormulaWon editorial teamLast reviewed September 2026