Identity: 1 + tan² = sec²
Derived Pythagorean identity dividing by cos².
Formula
Variables
How it works
This identity links two trig ratios for the same angle: the tangent and the secant. It comes from the Pythagorean identity \(\sin^2\theta + \cos^2\theta = 1\); if you divide every term by \(\cos^2\theta\), you get \(\tan^2\theta + 1 = \sec^2\theta\). The formula is true for every angle where \(\cos\theta \neq 0\), since both \(\tan\theta\) and \(\sec\theta\) must be defined.
When to use it
Use this identity when you need to simplify trig expressions, prove another identity, or rewrite everything in terms of tangent or secant. It is also useful in calculus and physics when expressions contain \(\tan\theta\) and \(\sec\theta\) together.
Worked example, step by step
Find \(\sec\theta\) if \(\tan\theta = 3\) and \(\theta\) is an angle where the identity applies. Start with \(1 + \tan^2\theta = \sec^2\theta\). Substitute \(\tan\theta = 3\): \(1 + 3^2 = \sec^2\theta\). Calculate: \(1 + 9 = \sec^2\theta\). So \(\sec^2\theta = 10\). Take the square root: \(\sec\theta = \pm\sqrt{10}\). If the quadrant or context shows \(\sec\theta\) is positive, then \(\sec\theta = \sqrt{10}\).
Common mistakes to avoid
- Forgetting that the identity is \(1 + \tan^2\theta = \sec^2\theta\), not \(1 + \tan\theta = \sec\theta\)
- Using the identity when \(\cos\theta = 0\), where tangent and secant are undefined
- Taking \(\sec\theta = \sqrt{1+\tan^2\theta}\) without considering that square roots can be positive or negative depending on the situation
Did You Know?
This identity is just the Pythagorean theorem in disguise, divided through by cos².
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More in Trigonometry
View allSine Ratio (SOH)
BasicRatio of the side opposite an angle to the hypotenuse.
Cosine Ratio (CAH)
BasicRatio of the side adjacent to an angle to the hypotenuse.
Tangent Ratio (TOA)
BasicRatio of the opposite side to the adjacent side.
Cosecant
IntermediateReciprocal of sine.
Secant
IntermediateReciprocal of cosine.
Cotangent
IntermediateReciprocal of tangent.