Trigonometry
Intermediate

Identity: 1 + cot² = csc²

Derived Pythagorean identity dividing by sin².

Formula

1+cot⁡2θ=csc⁡2θ1 + \cot^2\theta = \csc^2\theta

Variables

\thetaAngle

How it works

This identity says that if you take the reciprocal of sine and the quotient cosine over sine, their squares always fit a Pythagorean relationship. It comes directly from the basic identity sin²θ + cos²θ = 1: divide every term by sin²θ to get 1 + cot²θ = csc²θ. It is true for every angle where sin θ is not zero, since cot θ and csc θ are undefined when sine is zero.

When to use it

Use this identity when you need to simplify trigonometric expressions involving cotangent and cosecant, especially if a sine term is hidden in the problem. It is also useful in proofs, checking equivalence of expressions, and solving equations where converting everything to sine and cosine makes the algebra easier.

Worked example, step by step

Find csc²θ if cot θ = 3. Step 1: Substitute into the identity 1 + cot²θ = csc²θ. Step 2: csc²θ = 1 + 3² Step 3: csc²θ = 1 + 9 Step 4: csc²θ = 10 Final answer: csc²θ = 10.

Common mistakes to avoid

  • Forgetting that the identity uses squares, so cot θ = 3 gives cot²θ = 9, not 3
  • Using the identity when sin θ = 0, even though cot θ and csc θ are undefined there
  • Confusing this with 1 + tan²θ = sec²θ, which is a different Pythagorean identity

Did You Know?

Like its cousins, this identity is the circle's equation x²+y²=1 rewritten in reciprocal ratios.

Share this formula

Reviewed & maintained by the FormulaWon editorial teamLast reviewed September 2026