Thermodynamics & Heat
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Entropy Change

Reversible entropy change at temperature T.

Formula

ΔS=QT\Delta S = \frac{Q}{T}

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Variables

QHeat
TTemperature (K)

How it works

For a reversible process, the entropy change of a system is defined by the heat transferred in a tiny reversible step divided by the absolute temperature at which that step occurs, so for a constant-temperature reversible transfer this becomes ΔS = Q/T. This works because entropy measures how heat is dispersed among microscopic states, and dividing by Kelvin temperature captures the fact that the same amount of heat causes a smaller entropy change at higher temperature. The formula is only valid directly for reversible heat transfer; for irreversible processes you must compute ΔS from a reversible path between the same states.

When to use it

Use this when you know the heat exchanged reversibly at a fixed temperature, such as isothermal expansion/compression, phase changes at equilibrium, or idealized heat-transfer steps in thermodynamic cycles. It is also useful as a building block for finding total entropy change by summing many small reversible contributions.

Worked example, step by step

A liquid–vapour system absorbs 18.0 kJ of heat reversibly at 360 K during a phase change. Step 1: Write the formula: ΔS = Q/T Step 2: Convert heat to joules: Q = 18.0 kJ = 18,000 J Step 3: Substitute values: ΔS = 18,000 J / 360 K Step 4: Calculate: ΔS = 50 J/K Final answer: the entropy change is +50 J/K

Common mistakes to avoid

  • Using Celsius instead of Kelvin for temperature
  • Applying ΔS = Q/T to an irreversible process without using a reversible path
  • Forgetting that the sign of Q matters: heat absorbed gives positive ΔS, heat released gives negative ΔS

Did You Know?

Entropy was coined by Clausius from the Greek for "transformation", capturing the one-way flow of heat.

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Reviewed & maintained by the FormulaWon editorial teamLast reviewed September 2026