Thermodynamics & Heat
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Average KE of a Gas Molecule

Mean translational kinetic energy per molecule.

Formula

Eˉ=32kBT\bar{E} = \tfrac{3}{2}k_B T

Variables

k_BBoltzmann constant
TTemperature

How it works

This formula gives the average translational kinetic energy carried by one molecule of an ideal gas, and it depends only on absolute temperature, not on the gas species. It comes from the equipartition theorem: in thermal equilibrium, each of the three translational degrees of freedom contributes k_B T to the mean energy, so together they sum to /2 k_B T. That is why hotter gases have faster-moving molecules on average, and why the result is universal for ideal gases.

When to use it

Use this when you need the microscopic energy of gas molecules from temperature, especially in kinetic theory or ideal-gas problems. It is also useful for connecting temperature to molecular speed, internal energy, and thermal motion.

Worked example, step by step

Find the average translational kinetic energy of one nitrogen molecule at 400 K. Step 1: Write the formula E = (3/2)k_B T Step 2: Substitute values E = (3/2)(1.380649 d7 10^-23 J/K)(400 K) Step 3: Multiply the constants 1.380649 d7 10^-23 d7 400 = 5.522596 d7 10^-21 J Step 4: Multiply by 3/2 E = 1.5 d7 5.522596 d7 10^-21 J = 8.283894 d7 10^-21 J Final answer: E  8.28 d7 10^-21 J per molecule

Common mistakes to avoid

  • Using Celsius instead of Kelvin for T
  • Confusing average kinetic energy per molecule with total gas internal energy
  • Applying the formula to non-ideal situations without checking whether the gas model is valid

Did You Know?

Temperature is really just the average kinetic energy of molecules, so "hot" means "jiggling faster".

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Reviewed & maintained by the FormulaWon editorial teamLast reviewed September 2026