Frequency Resolution
Spacing between adjacent FFT bins.
Formula
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Example
f_s=44100, N=4096: Δf ≈ 10.8 Hz
How it works
In an FFT, the sampled signal is represented by a fixed number of evenly spaced frequency bins across the available frequency range. The bin spacing is the sampling rate divided by the FFT length, so increasing N makes the frequency grid finer while increasing f_s spreads the same number of bins over a wider range. This is why a longer FFT gives better ability to distinguish nearby tones in the spectrum.
When to use it
Use this when you want to know how close two spectral peaks can be before they appear in separate FFT bins. It is especially useful in audio analysis, vibration monitoring, communications, and any system where you need to choose an FFT size for a desired frequency detail.
Worked example, step by step
Given: f_s = 48,000 Hz and N = 2,048 Step 1: Write the formula: Δf = f_s / N Step 2: Substitute the values: Δf = 48,000 / 2,048 Step 3: Calculate: Δf = 23.4375 Hz Final answer: the FFT bin spacing is about 23.44 Hz, so adjacent bins are separated by roughly 23.44 Hz.
Common mistakes to avoid
- Confusing FFT size with the number of visible peaks instead of the number of points used in the transform
- Using the Nyquist frequency f_s/2 in the formula instead of the full sampling rate f_s
- Assuming smaller bin spacing alone guarantees perfect ability to separate two close frequencies
Did You Know?
Finer frequency resolution needs a longer analysis window — the classic time-frequency trade-off.
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