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Settling Time (approx.)

Time for a control response to settle within 2% of target.

Formula

ts≈4ζωnt_s \approx \frac{4}{\zeta \omega_n}

Variables

t_sSettling time (s)
ζDamping ratio
ω_nNatural frequency (rad/s)

Example

ζ=0.7, ω_n=10: t_s ≈ 0.57 s

How it works

This approximation estimates how long a lightly damped second-order system takes to enter and stay within a small band around its final value, commonly the 2% band. It comes from the exponential decay envelope of a standard underdamped response: the oscillation amplitude shrinks roughly like e^{-\zeta\omega_n t}, and solving for when that envelope drops to about 2% gives the constant 4 in the numerator. The result is most accurate for systems that behave like a dominant second-order mode with moderate damping, and it gives a quick engineering estimate rather than an exact value.

When to use it

Use this when analyzing or tuning second-order control systems such as servo motors, drones, suspension models, or feedback loops where overshoot and settling are important. It is especially useful during early design or controller tuning when you know the damping ratio and natural frequency and want a fast estimate of response speed.

Worked example, step by step

Given: ζ = 0.5, ω_n = 8 rad/s Step 1: Write the approximation t_s ≈ 4 / (ζω_n) Step 2: Substitute the values t_s ≈ 4 / (0.5 × 8) Step 3: Multiply the denominator t_s ≈ 4 / 4 Step 4: Compute the result t_s ≈ 1.0 s So the settling time is approximately 1.0 second.

Common mistakes to avoid

  • Using the formula for a system that is not approximately second-order dominant
  • Confusing settling time with rise time or peak time
  • Forgetting that the 4/(ζω_n) rule is an approximation for a 2% settling band, not an exact identity

Did You Know?

A damping ratio near 0.7 gives the sweet spot — fast settling with barely any overshoot.

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Reviewed & maintained by the FormulaWon editorial teamLast reviewed September 2026