Standing Wave (String)
Harmonic frequencies of a fixed string.
Formula
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How it works
A stretched string fixed at both ends can only vibrate in certain patterns, because each end must be a node where the displacement is always zero. Those allowed patterns fit an integer number of half-wavelengths into the string length, so the wavelength is \u03bb_n = 2L/n and the frequency becomes f_n = v/\u03bb_n = nv/(2L). Larger n means more half-waves on the string and a proportionally higher pitch.
When to use it
Use this when analyzing harmonics of a string on instruments like guitars, violins, or a lab string under tension. It is also useful in physics problems that give the wave speed on a fixed string and ask for an overtone or harmonic frequency.
Worked example, step by step
A string of length L = 0.75 m supports transverse waves at speed v = 180 m/s. Find the 4th harmonic frequency. Use f_n = nv/(2L) Substitute n = 4, v = 180 m/s, L = 0.75 m f_4 = (4)(180) / (2 \u00d7 0.75) f_4 = 720 / 1.5 f_4 = 480 Hz So the 4th harmonic frequency is 480 Hz.
Common mistakes to avoid
- Using the full wavelength instead of the half-wavelength condition for a string fixed at both ends
- Forgetting that n counts harmonics: n = 1 is the fundamental, n = 2 is the first overtone, and so on
- Mixing up string length L with wavelength \u03bb, or using the wrong wave speed units
Did You Know?
A guitar string sings because standing waves fit only certain wavelengths between its fixed ends.
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