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Standing Wave (String)

Harmonic frequencies of a fixed string.

Formula

fn=nv2Lf_n = \frac{nv}{2L}

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Variables

nHarmonic number
vWave speed
LLength

How it works

A stretched string fixed at both ends can only vibrate in certain patterns, because each end must be a node where the displacement is always zero. Those allowed patterns fit an integer number of half-wavelengths into the string length, so the wavelength is \u03bb_n = 2L/n and the frequency becomes f_n = v/\u03bb_n = nv/(2L). Larger n means more half-waves on the string and a proportionally higher pitch.

When to use it

Use this when analyzing harmonics of a string on instruments like guitars, violins, or a lab string under tension. It is also useful in physics problems that give the wave speed on a fixed string and ask for an overtone or harmonic frequency.

Worked example, step by step

A string of length L = 0.75 m supports transverse waves at speed v = 180 m/s. Find the 4th harmonic frequency. Use f_n = nv/(2L) Substitute n = 4, v = 180 m/s, L = 0.75 m f_4 = (4)(180) / (2 \u00d7 0.75) f_4 = 720 / 1.5 f_4 = 480 Hz So the 4th harmonic frequency is 480 Hz.

Common mistakes to avoid

  • Using the full wavelength instead of the half-wavelength condition for a string fixed at both ends
  • Forgetting that n counts harmonics: n = 1 is the fundamental, n = 2 is the first overtone, and so on
  • Mixing up string length L with wavelength \u03bb, or using the wrong wave speed units

Did You Know?

A guitar string sings because standing waves fit only certain wavelengths between its fixed ends.

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Reviewed & maintained by the FormulaWon editorial teamLast reviewed September 2026